Python Seaborn Matplotlib 设置线型为图例

Question

我使用 factorplot() 方法用 seaborn 构建了以下情节。

是否可以使用线型作为图例来代替右侧基于线色的图例？

graycolors = sns.mpl_palette('Greys_r', 4)
g = sns.factorplot(x="k", y="value", hue="class", palette=graycolors,
                   data=df, linestyles=["-", "--"])

此外，我试图在我的 factorplot 方法中使用 color="black" 参数使两条线都变成黑色，但这会导致异常“factorplot() 得到了一个意外的关键字参数 'color'” .如何用相同的颜色绘制两条线并仅通过线型将它们分开？

Answer 1

我一直在寻找一种解决方案，试图将线型放入图例中，例如 matplotlib, but I have not yet found how to do this in seaborn. However, to make the data clear in the legend I have used different markers:

import seaborn as sns
import numpy as np
import pandas as pd

# creating some data
n = 11
x = np.linspace(0,2, n)
y = np.sin(2*np.pi*x)
y2 = np.cos(2*np.pi*x)
data = {'x': np.append(x, x), 'y': np.append(y, y2),
        'class': np.append(np.repeat('sin', n), np.repeat('cos', n))}
df = pd.DataFrame(data)

# plot the data with the markers
# note that I put the legend=False to move it up (otherwise it was blocking the graph)
g=sns.factorplot(x="x", y="y", hue="class", palette=graycolors,
                 data=df, linestyles=["-", "--"], markers=['o','v'], legend=False)
# placing the legend up
g.axes[0][0].legend(loc=1)
# showing graph
plt.show()

Answer 2

您可以尝试以下方法：

h = plt.gca().get_lines()
lg = plt.legend(handles=h, labels=['YOUR Labels List'], loc='best')

我用得很好。

Python Seaborn Matplotlib 设置线型为图例

Python Seaborn Matplotlib setting line style as legend

python

plot

matplotlib

seaborn