从 NSMutableArray 中删除重复的坐标

Question

我有一个坐标数组，它是字符串。所以一个字符串是一个坐标，纬度和经度用逗号分隔。

例如：47.551170,18.961630

所以我的数组看起来像这样：

 47.551090,18.961610
 47.551010,18.961600
 47.550910,18.961600
 47.550830,18.961610
 47.550750,18.961640
 47.550690,18.961680
 47.549980,18.962870
 47.549170,18.964170
 47.548950,18.964500
 47.548840,18.964620
 47.548710,18.964690
 47.548470,18.964690
 47.548400,18.964690
 47.547990,18.964720

如果一个坐标的纬度或经度与数组中另一个坐标的纬度或经度匹配，我该如何删除该坐标？

Answer 1

您需要将这些字符串转换为 CLLocationCoordinate2D 对象，以便您可以比较值而不是字符串。如果您提供 == 覆盖，则可以使用 swift 的 contains 方法轻松创建一个唯一坐标数组，如下所示：

var coordinates: [CLLocationCoordinate2D] = []
for string in stringArray {
    let coordinateStrings = string.componentsSeparatedByString(",")
    let coordinate = CLLocationCoordinate2D(latitude: Double(coordinateStrings[0])!, longitude: Double(coordinateStrings[1])!)
    coordinates.append(coordinate)
}

func ==(lhs: CLLocationCoordinate2D, rhs: CLLocationCoordinate2D) -> Bool {
    //If you really do mean lat OR long, then change the && to ||
    return lhs.latitude == rhs.latitude && lhs.longitude == rhs.longitude
}

var uniqueCoordinates: [CLLocationCoordinate2D] = []
for coordinate in coordinates {
    if !uniqueCoordinates.contains(coordinate) {
        uniqueCoordinates.append(coordinate)
    }
}

然后，如果您想将这些坐标转换回字符串，您可以这样做：

var uniqueStrings: [String] = []
for coordinate in uniqueCoordinates {
    let uniqueString = String(format: "%f,%f", coordinate.latitude,coordinate.longitude)
    uniqueStrings.append(uniqueString)
}

Answer 2

使用NSOrderedSet、NSMutableSet或NSSet非常简单，只存储不同的值，它会自动忽略重复值。

The NSMutableSet class declares the programmatic interface to a mutable, unordered collection of distinct objects.

NSOrderedSet and its subclass, NSMutableOrderedSet, declare the programmatic interfaces to an ordered collection of objects.

在Apple Documentation about NSMutableSet and NSOrderedSet Class Reference

中阅读更多内容

NSOrderedSet *uniqueSet = [NSOrderedSet setWithObjects:@"47.551090,18.961610",
@"47.551010,18.961600",
@"47.550910,18.961600",
@"47.550830,18.961610",
@"47.550750,18.961640",
@"47.550690,18.961680",
@"47.549980,18.962870",
@"47.549170,18.964170",
@"47.548950,18.964500",
@"47.548840,18.964620",
@"47.548710,18.964690",
@"47.548470,18.964690",
@"47.548400,18.964690",
@"47.547990,18.964720", nil];

NSLog(@"Unique List : %@",uniqueSet);

通过多次添加任何值来检查它，它只会在您登录时显示一次。

编码愉快:)

Answer 3

尝试使用 NSMutableSet:-

NSMutableArray *Array1 = @[@"47.551090,18.961610",
@"47.551010,18.961600",
@"47.550910,18.961600",
@"47.550830,18.961610",
@"47.550750,18.961640",
@"47.550690,18.961680",
@"47.549980,18.962870",
@"47.549170,18.964170",
@"47.548950,18.964500",
@"47.548840,18.964620",
@"47.548710,18.964690",
@"47.548470,18.964690",
@"47.548400,18.964690",
@"47.547990,18.964720", nil];

NSMutableSet *uniqueMakes = [NSMutableSet setWithArray:Array1];

现在，如果您使用 NSLog 打印 uniqueMakes，那么它只打印那些唯一的，在此之后您可以在 MapView 上显示这些值。

如果您想了解更多有关 NSSet 的信息，请转到此 link http://rypress.com/tutorials/objective-c/data-types/nsset .

Answer 4

NSArray *Array1 = @[@"47.551090,18.961610",
                           @"47.551010,18.961600",
                           @"47.550910,18.961600",
                           @"47.550830,18.961610",
                           @"47.550750,18.961640",
                           @"47.550690,18.961680",
                           @"47.549980,18.962870",
                           @"47.549170,18.964170",
                           @"47.548950,18.964500",
                           @"47.548840,18.964620",
                           @"47.548710,18.964690",
                           @"47.548470,18.964690",
                           @"47.548400,18.964690",
                           @"47.547990,18.964720"];

NSMutableArray *finalArr=[[NSMutableArray alloc] init];
for (NSString *str in Array1) {
    NSArray *temp=[str componentsSeparatedByString:@","];
    if(temp!=nil && [temp count]==2){
        BOOL isSame=NO;
        for(NSString *s in finalArr){
             NSArray *temp2=[s componentsSeparatedByString:@","];
            if([[temp objectAtIndex:0] isEqualToString:[temp2 objectAtIndex:0]]){
                isSame=YES;
                break;
            }

            if([[temp objectAtIndex:1] isEqualToString:[temp2 objectAtIndex:1]]){
                isSame=YES;
                break;
            }
        }

        if(isSame==NO){
            [finalArr addObject:str];
        }
    }
}
NSLog(@"%@",finalArr);

从 NSMutableArray 中删除重复的坐标

Remove duplicate coordinates from NSMutableArray

objective-c

nsmutablearray

ios