SQL 错误 "Cannot perform an aggregate function on an expression containing an aggregate or a sub query."

Question

我正在 Oracle 中执行此查询。我已经添加了我的数据和 returned 结果的屏幕截图，但是 returned 结果是错误的。它是 returning 1 但它应该 return 0.52。因为客户（见附件截图）的代码为 1、2、4、31，对于 1、2、4，他应该得到 0.70 值，对于 31，他应该得到 0.75，然后乘法后 returned 结果应该为 0.52 而不是 1。我真的被困在这里了。请帮我。我会非常感谢你的。

这是我的查询。我真正想做的是，我想根据每个客户获得的代码计算给予每个客户的积分值。

如果客户的代码为 1，那么他将获得 0.70 分，如果他的代码也为 2 和 4，那么我不想为代码 2 和 4 多给他 0.70 分。

让我简单点。如果客户拥有所有这些代码 1、2、4，那么他一次只能获得 0.70 积分，但如果他只有代码 4，那么他将获得 0.90，但如果他也有代码 31，那么他将获得额外的 0.75 积分有代码 31。现在有意义吗？

       SELECT 
       RM_LIVE.EMPLOYEE.EMPNO, RM_LIVE.EMPNAME.FIRSTNAME,
       RM_LIVE.EMPNAME.LASTNAME, RM_LIVE.CRWBASE.BASE ,RM_LIVE.CRWCAT.crwcat AS "Rank",
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN (29,721) THEN 0.25 ELSE 1 END),0),1) *
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN (31,723) THEN 0.75 ELSE 1 END),0),1) *
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC = 861 THEN 0.80 ELSE 1 END),0),1) *
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN (17,302,16) THEN 0.85 ELSE 1 END),0),1) *
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN (3,7) THEN 0.90 ELSE 1 END),0),1)*
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN (921,301,30,722,601,581) THEN 0.50 ELSE 1 END),0),1) *
       nvl(nullif(MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN (2,1, 4) THEN 0.70 ELSE 1 END),0),1) *
       nvl(nullif(MIN(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC  IN (1,2) then 0 else 1 END) * 
                  MAX(CASE WHEN RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC  IN (4) then 0.20 else 0 END),0),1) AS "FTE VALUE"

     FROM RM_LIVE.EMPBASE,
     RM_LIVE.EMPLOYEE,
     RM_LIVE.CRWBASE,
     RM_LIVE.EMPNAME,
     RM_LIVE.CRWSPECFUNC,
     RM_LIVE.EMPSPECFUNC,RM_LIVE.EMPQUALCAT,RM_LIVE.CRWCAT
       where RM_LIVE.EMPBASE.IDEMPNO = RM_LIVE.EMPLOYEE.IDEMPNO
        AND RM_LIVE.EMPBASE.IDCRWBASE = RM_LIVE.CRWBASE.IDCRWBASE
         AND RM_LIVE.EMPLOYEE.IDEMPNO = RM_LIVE.EMPNAME.IDEMPNO 
          AND RM_LIVE.EMPSPECFUNC.IDCRWSPECFUNC =RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC  
           AND RM_LIVE.EMPSPECFUNC.IDEMPNO =RM_LIVE.EMPLOYEE.IDEMPNO
            AND  RM_LIVE.EMPQUALCAT.IDEMPNO=RM_LIVE.EMPLOYEE.IDEMPNO 
             AND  RM_LIVE.CRWCAT.IDCRWCAT = RM_LIVE.EMPQUALCAT.IDCRWCAT
              AND RM_LIVE.CRWCAT.crwcat IN ('CP','FO','CM','MC')
               AND RM_LIVE.CRWBASE.BASE <> 'XYZ'
                AND RM_LIVE.CRWSPECFUNC.IDCRWSPECFUNC IN  
                ('921','2' ,'1','301','17','4','3','7','302' ,'861','31',
                 '723','30','722 ','29 ','721','16','601','581')  
                  AND RM_LIVE.EMPBASE.STARTDATE <= SYSDATE
                   AND RM_LIVE.EMPBASE.ENDDATE >= SYSDATE
                    AND RM_LIVE.EMPSPECFUNC.STARTDATE <= SYSDATE
                     AND RM_LIVE.EMPSPECFUNC.ENDDATE >= SYSDATE
                      AND RM_LIVE.EMPNAME.FROMDATE <=SYSDATE
                       AND RM_LIVE.EMPQUALCAT.STARTDATE <= SYSDATE
                        AND RM_LIVE.EMPQUALCAT.ENDDATE >= SYSDATE
       GROUP BY RM_LIVE.EMPLOYEE.EMPNO, RM_LIVE.EMPNAME.FIRSTNAME,
       RM_LIVE.EMPNAME.LASTNAME, RM_LIVE.CRWBASE.BASE,RM_LIVE.CRWCAT.crwcat;

Answer 1

您在计算总和之前漏掉了一个逗号 (,)。

所以你的代码应该是：

SELECT [id]
  ,[name]
  ,SUM(CASE WHEN (SELECT [code] 
                   FROM [Test].[dbo].[testcode] as ts 
                   WHERE ts.id = t.id) IN (1,2,4) 
            then 100 
            else 10 
           end) as "total" 
  FROM [Test].[dbo].[testcode] as t 
  GROUP BY id, name

Answer 2

您已经从 testcode table 中进行选择 - 无需在 CASE 表达式中执行任何子查询 - 只需使用此代码：

SELECT 
    [id], [name],
    SUM(CASE 
           WHEN [code] IN (1, 2, 4) 
               THEN 100 
           WHEN [code] = 8
               THEN 80
        END) AS [total] 
FROM 
    [Test].[dbo].[testcode] AS t 
GROUP BY 
    id, name

Answer 3

根据期望的结果评论，试试这个

SELECT [id]
  ,[name]
  , r = max(CASE WHEN [code]  IN (1,2,4) then 100 else 0 end)
    + max(CASE WHEN [code] IN (8) then 80 else 0 end)
  FROM 
    -- your table here
    (values (1, 'ali',4)
            ,(1, 'ali',1)
            ,(1, 'ali',8)
    ) as t(id, name,code)
  GROUP BY id, name;

编辑另一个排除某些东西的故事。 1,2,4 中的任何一个都给 100 如果只有 4 没有 (1,2) 加 400.

SELECT [id]
  ,[name]
  , r = max(CASE WHEN [code]  IN (1,2,4) then 100 else 0 end)
    + min(CASE WHEN [code]  IN (1,2) then 0 else 1 end) 
        * max(CASE WHEN [code]  IN (4) then 400 else 0 end)
    + max(CASE WHEN [code] IN (8) then 80 else 0 end)
  FROM 
    -- your table here
    (values (1, 'ali',4)
            ,(1, 'ali',1)
            ,(1, 'ali',8)
            ,(2, 'ali',4)
            ,(2, 'ali',8)
    ) as t(id, name,code)
  GROUP BY id, name;

编辑 2 如果你需要分数相乘，请将 + 替换为 * 并将 0 转换为 1。

SELECT [id]
  ,[name]
  ,r = isnull(nullif(
        max(CASE WHEN [code]  IN (1,2,4) then 100 else 0 end)
      ,0),1)
    * isnull(nullif(
       min(CASE WHEN [code]  IN (1,2) then 0 else 1 end) 
        * max(CASE WHEN [code]  IN (4) then 400 else 0 end)
      ,0),1)
    * isnull(nullif(
        max(CASE WHEN [code] IN (8) then 80 else 0 end)
      ,0),1)
  FROM 
    -- your table here
    (values (1, 'ali',4)
            ,(1, 'ali',1)
            ,(1, 'ali',8)
            ,(2, 'ali',4)
            ,(2, 'ali',8)
    ) as t(id, name,code)
  GROUP BY id, name;

SQL 错误 "Cannot perform an aggregate function on an expression containing an aggregate or a sub query."

SQL Error "Cannot perform an aggregate function on an expression containing an aggregate or a sub query."

sql

sql-server

sql-server-2005

sql-server-2008

sql-server-2008-r2