将具有多个元素的文本文件读入数组列表（设置和获取）

Question

我正在尝试读取类型（艺术家、标题、流派、唱片公司、发行年份、歌曲数量、播放时间）的文本文件：

The Beatles, Abbey Road, Rock, Apple Records, 1969, 17, 47.16

Sia, 1000 种恐惧形式, Pop, Intertia, 2014, 12, 48.41

泰勒Swift，现在发言

我已经创建了一张 CD class:

package q;

public class CD {
  // 
  private String artist;
  private String titel;
  private String genre;
  private String recordcompany;
  private int year; // 
  private int songs; // 
  private double playtime; // 


  public CD() { // 
  }
  public CD(String newArtist, String newTitel) {
    artist = newArtist;
    titel = newTitel;
  }
  public CD(String newArtist, String newTitel, String newGenre, String newRecordcompany, int newYear, int newSongs, double newPlaytime) {
    artist = newArtist;
    titel = newTitel;
    genre = newGenre;
    recordcompany = newRecordcompany;
    year = newYear;
    songs = newSongs;
    playtime = newPlaytime;
  }

  public String getArtist() { //  
    return artist;
  }
  public String getTitel() {
    return titel;
  }
  public String getGenre() {
    return genre;
  }
  public String getRecordcompany() {
    return recordcompany;
  }
  public int getYear() {
    return year;
  }
  public int getsong() {
    return songs;
  }
  public double getPlaytime() {
    return playtime;
  }
  public void setArtist(String newArtist) { // 
    artist = newArtist;
  }
  public void setTitel(String newTitel) {
    titel = newTitel;
  }
  public void setGenre(String newGenre) {
    genre = newGenre;
  }
  public void setRecordcompany(String newRecordcompany) {
    recordcompany = newRecordcompany;
  }
  public void setYear(int newYear) {
    year = newYear;
  }
  public void setSongs(int newSongs) {
    songs = newSongs;
  }
  public void setplaytime(double newPlaytime) {
    playtime = newPlaytime;
  }

  @
  Override public String toString() { // 
    return ("Artist " + artist + System.lineSeparator() + "Titel: " + titel + System.lineSeparator() + "Genre: " + genre + System.lineSeparator() + "Recordcompany: " + recordcompany + System.lineSeparator() + "Year: " + year + System.lineSeparator() + "Songs: " + songs + System.lineSeparator() + "Playtime: " + playtime + System.lineSeparator());
  }
}

我正在尝试从文本文件中读取，然后将其转换为数组列表。我知道我首先将文本文件转换为字符串数组，然后将其转换为数组列表，从而使它过于复杂。如果可能的话，我想在创建数组时使用 set 和 get 方法。我想知道你们中的任何人是否有任何提示可以让我如何使代码不那么复杂并尽可能包含 set 和 get 方法，谢谢。

package q;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Arrays;
import java.util.List;


public class Q {


  public static void main(String[] args) throws FileNotFoundException {


    String artist = "";
    String titel = "";
    String genre = "";
    String recordcompany = "";
    String year = "";
    String songs = "";
    String playtime = "";


    try {
      BufferedReader br = new BufferedReader(new FileReader("nej.txt"));
      String line = null;

      while ((line = br.readLine()) != null) {
        String tmp[] = line.split(",");
        artist = tmp[0];
        titel = tmp[1];

        if (tmp.length > 2) {
          genre = tmp[2];
          recordcompany = tmp[3];
          year = (tmp[4]);
          songs = (tmp[5]);
          playtime = (tmp[6]);
        } else {
          genre = "";
          recordcompany = "";
          year = "";
          songs = "";
          playtime = "";

        }
        List < String > unsorted = Arrays.asList(tmp);
        for (String e: unsorted) {
          System.out.println(e);
        }
      }

      br.close();
    } catch (IOException e) {
      System.out.println(e);
    }
  }
}

已编辑

package q;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;


public class Q {


  public static void main(String[] args) throws FileNotFoundException {


    String artist = "";
    String titel = "";
    String genre = "";
    String recordcompany = "";
    int year = 0;
    int songs = 0;
    double playtime = 0.0;



    try {
      BufferedReader br = new BufferedReader(new FileReader("nej.txt"));
      String line = null;

      List < CD > cdsList = new ArrayList < > ();

      while ((line = br.readLine()) != null) {
        CD cd = new CD();
        String tmp[] = line.split(",");
        cd.setArtist(tmp[0]);
        cd.setTitel(tmp[1]);

        if (tmp.length > 2) {
          cd.setGenre(tmp[2]);
          cd.setRecordcompany(tmp[3]);
          cd.setYear(Integer.parseInt(tmp[4].trim()));
          cd.setSongs(Integer.parseInt(tmp[5].trim()));
          cd.setplaytime(Double.parseDouble(tmp[6].trim()));

        }
        System.out.println(cdsList);
      }

      br.close();

    } catch (IOException e) {
      System.out.println(e);
    }

  }
}

Answer 1

类似下面的内容。

public static void main(String[] args) {
        try {
          BufferedReader br = new BufferedReader(new FileReader("nej.txt"));
          String line = null;

          List < CD > cdsList = new ArrayList < > ();

          while ((line = br.readLine()) != null) {
            CD cd = new CD();
            String tmp[] = line.split(",");
            cd.setArtist(tmp[0]);
            cd.setTitel(tmp[1]);

            if (tmp.length > 2) {
              cd.setGenre(tmp[2]);
              cd.setRecordcompany(tmp[3]);
              cd.setYear(Integer.parseInt(tmp[4].trim()));
              cd.setSongs(Integer.parseInt(tmp[5].trim()));
              cd.setplaytime(Double.parseDouble(tmp[6].trim()));

            }
            cdsList.add(cd);

          }
          System.out.println(cdsList);

          br.close();

        } catch (IOException e) {
          System.out.println(e);
        }

}

将具有多个元素的文本文件读入数组列表（设置和获取）

Reading textfile with multiple elements into arraylist (set and get)

java

arraylist

text-files

readfile