PostgreSQL 连接子查询不能限制查询

PostgreSQL join subquery can't restrict query

将此问题移至 DBA STACKEXCHANGE: https://dba.stackexchange.com/questions/137878/postgresql-join-subquery-cant-restrict-query

我正在做一个支票拆分项目,该项目拆分 activity 的欠款。用户可以属于多个 'groups',每个用户都有自己的 运行ning 余额。

我正在尝试 运行 一个查询,该查询将 return 个人用户 'amount owed' 跨所有组。

目前查询如下所示:

SELECT 
    SUM(owe) 
FROM (
    SELECT 
        (expenses.amount/count(*))
    AS owe 
    FROM expenses 
    LEFT JOIN user_expenses 
    ON (
        expenses.id = user_expenses.expense_id
        ) 
    WHERE expenses.paid_by != 1 
    GROUP BY expenses.id
    ) 
AS total;

问题是此查询全面检索所有费用。我想做的是通过使用限制:

WHERE user_expenses.user_id = 1

如何将其添加到上述查询(在子查询中)以将结果限制为仅与该用户关联的费用?

TABLE 架构(如果有帮助的话):

USERS
id
name
username
email

EXPENSES
id
created_at
updated_at
title
amount
group_id
paid_by
img_url
note

USER_EXPENSES (join table)
id
expense_id
user_id

GROUPS
id
created_at
name
desc

USER_GROUPS
id
user_id
group_id

更多示例信息以供说明: 如果我 运行 这个查询 -

SELECT 
    e.title,
    e.amount,
    (e.amount/count(*)) AS owe, count(*) AS members 
      FROM expenses e LEFT JOIN
           user_expenses ue
           ON e.id = ue.expense_id
      WHERE e.paid_by != 1 
      GROUP BY e.id;

我得到这样的结果(带有虚拟数据):

如果我运行以下:

SELECT 
    e.title,
    e.amount,
    (e.amount/count(*)) AS owe, count(*) AS members 
      FROM expenses e LEFT JOIN
           user_expenses ue
           ON e.id = ue.expense_id AND ue.user_id = 1
      WHERE e.paid_by != 1 
      GROUP BY e.id;

我明白了(注意成员数):

如果您的查询有效,那么您只需将其添加到子查询中:

SELECT SUM(owe) 
FROM (SELECT (e.amount/count(*)) AS owe 
      FROM expenses e LEFT JOIN
           user_expenses ue
           ON e.id = ue.expense_id AND ue.user_id = 1
      WHERE expenses.paid_by <> 1 
      GROUP BY expenses.id
     ) t;

我们最终得出了两个解决方案。非常感谢一位了不起的团队成员,他通过它提供了强大的支持,并做出了一些有用的东西,而且可以认为它更便宜一些。尽管如此,还是要感谢他们。

事实证明,HAVING 是获得所需解决方案的关键部分(感谢@andriy-m):

HAVING clause was added to SQL because the WHERE keyword could not be used with aggregate functions

SELECT SUM(owe) 
FROM (
  SELECT 
    (e.amount/count(*)) AS owe 
  FROM expenses e 
  LEFT JOIN
       user_expenses ue
  ON e.id = ue.expense_id
  WHERE e.paid_by != 1 
  GROUP BY e.id
  HAVING COUNT(ue.user_id = 1 OR NULL) > 0
) 
AS total;

另外,向为此付出努力的 PJ 表示敬意:

SELECT SUM(owe) 
FROM (SELECT (expenses.amount/count(*)) AS owe 
FROM expenses 
LEFT JOIN user_expenses ON (expenses.id = user_expenses.expense_id) 
WHERE expenses.paid_by != 1 
AND expense_id IN (select expense_id from users LEFT JOIN user_expenses 
ON (1 = user_expenses.user_id)) GROUP BY expenses.id)
AS total;