如何访问 JAX-RS 资源？

Question

我已经为我的 Java 基于 EE 的项目创建了一个简单的 JAX-RS 资源 class。我正在尝试从服务器获取响应，但是当我访问我的 url 时，我收到错误消息。这是我写的class：

@Path("/rest")
public class RestResource {

    @GET
    @Produces(MediaType.APPLICATION_JSON)
    public String create(String name)
    {
        return "print my string";
    }
}

我不知道我做错了什么。我必须在 web.xml 中定义一个新的 servlet 吗？我现在的有问题吗？

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
    metadata-complete="false">

    <session-config>
        <session-timeout>30</session-timeout>
    </session-config>

    <display-name>crud-app</display-name>

    <!-- Activate the JSF 2.0 servlet -->
    <servlet>
        <servlet-name>Faces Servlet</servlet-name>
        <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <!-- Tell the context which URLs to send through JSF -->
    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>*.xhtml</url-pattern>
    </servlet-mapping>

    <!-- This is an optional parameter, but it makes troubleshooting errors 
        much easier -->
    <!-- You are advised to remove this context parameter before a production 
        deployment -->
    <context-param>
        <param-name>facelets.DEVELOPMENT</param-name>
        <param-value>true</param-value>
    </context-param>

    <!-- Welcome page -->
    <welcome-file-list>
        <welcome-file>person.jsf</welcome-file>
    </welcome-file-list>

    <error-page>
        <exception-type>java.lang.Throwable</exception-type>
        <location>/ui/error/error.jsf</location>
    </error-page>
    <error-page>
        <exception-type>javax.faces.application.ViewExpiredException</exception-type>
        <location>/ui/error/viewExpired.jsf</location>
    </error-page>
</web-app>

Answer 1

我设法通过使用 RESTEasy 解决了我的问题。这是我更新的 web.xml 文件：

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
    metadata-complete="false">

    <session-config>
        <session-timeout>30</session-timeout>
    </session-config>

    <display-name>crud-app</display-name>

    <!-- Activate the JSF 2.0 servlet -->
    <servlet>
        <servlet-name>Faces Servlet</servlet-name>
        <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <!-- Tell the context which URLs to send through JSF -->
    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>*.xhtml</url-pattern>
    </servlet-mapping>

    <!-- Auto scan REST service -->
    <context-param>
        <param-name>resteasy.scan</param-name>
        <param-value>true</param-value>
    </context-param>

    <!-- this need same with resteasy servlet url-pattern -->
    <context-param>
        <param-name>resteasy.servlet.mapping.prefix</param-name>
        <param-value>/rest</param-value>
    </context-param>

    <listener>
        <listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
    </listener>

    <servlet>
        <servlet-name>resteasy-servlet</servlet-name>
        <servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
    </servlet>

    <servlet-mapping>
        <servlet-name>resteasy-servlet</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>

    <!-- This is an optional parameter, but it makes troubleshooting errors 
        much easier -->
    <!-- You are advised to remove this context parameter before a production 
        deployment -->
    <context-param>
        <param-name>facelets.DEVELOPMENT</param-name>
        <param-value>true</param-value>
    </context-param>

    <!-- Welcome page -->
    <welcome-file-list>
        <welcome-file>person.jsf</welcome-file>
    </welcome-file-list>

    <error-page>
        <exception-type>java.lang.Throwable</exception-type>
        <location>/ui/error/error.jsf</location>
    </error-page>
    <error-page>
        <exception-type>javax.faces.application.ViewExpiredException</exception-type>
        <location>/ui/error/viewExpired.jsf</location>
    </error-page>
</web-app>

如何访问 JAX-RS 资源？

How can I access a JAX-RS resource?

jax-rs

http-status-code-404