尝试使用#define 将字符串数组分配给变量时出错（无效的初始值设定项错误）

Question

我正在尝试编译包含以下行的 C 代码：

//...
#ifdef CPU_GPREG_NAMES
static const char *reg_names[] = CPU_GPREG_NAMES;
#endif
//...

其中宏 CPU_GPREG_NAMES 定义为：

#define CPU_GPREG_NAMES                                            \
"zero", "at", "v0", "v1", "a0", "a1", "a2", "a3",                  \
"t0", "t1", "t2", "t3", "t4", "t5", "t6", "t7",                    \
"s0", "s1", "s2", "s3", "s4", "s5", "s6", "s7",                    \
"t8", "t9", "k0", "k1", "gp", "sp", "fp", "ra"                     \

但是上面第一个代码片段中的赋值似乎有问题，因为我在该特定行上收到以下错误：

error: invalid initializer
error: expected identifier or '(' before string constant

这个错误的原因是什么？

Answer 1

您的初始化程序需要花括号。因为你正在初始化的是一个数组，大括号表示你正在设置数组的多个元素：

#define CPU_GPREG_NAMES {                                          \
"zero", "at", "v0", "v1", "a0", "a1", "a2", "a3",                  \
"t0", "t1", "t2", "t3", "t4", "t5", "t6", "t7",                    \
"s0", "s1", "s2", "s3", "s4", "s5", "s6", "s7",                    \
"t8", "t9", "k0", "k1", "gp", "sp", "fp", "ra" }

Answer 2

你忘了放花括号：

#define CPU_GPREG_NAMES  {                              \
    "zero", "at", "v0", "v1", "a0", "a1", "a2", "a3",   \
    "t0", "t1", "t2", "t3", "t4", "t5", "t6", "t7",     \
    "s0", "s1", "s2", "s3", "s4", "s5", "s6", "s7",     \
    "t8", "t9", "k0", "k1", "gp", "sp", "fp", "ra"      \
}

或

static const char *reg_names[] = {CPU_GPREG_NAMES};

Answer 3

您需要花括号来为初始化程序定义数组。你可以这样做：

#define CPU_GPREG_NAMES { \
     "zero", ... \
     ... \
}

或

static const char *reg_names[] = {CPU_GPREG_NAMES};

尝试使用#define 将字符串数组分配给变量时出错（无效的初始值设定项错误）

Error when trying to assign array of strings to a variable using #define (invalid initializer error)

c

string

macros

variable-assignment