如何在 R 中按名称模式删除行？

Question

我的示例数据集如下所示。

Country      Population        Capital             Area
A            210000210         Sydney/Landon       10000000
B            420000000         Landon              42100000
C            500000            Italy42/Rome1       9200000   
D            520000100         Dubai/Vienna21A     720000

如何删除列中具有模式 / 的整行。我试图查看以下 link R: Delete rows based on different values following a certain pattern，但没有帮助。

Answer 1

你可以试试grepl

df[!grepl('[/]', df$Capital),]
#   Country Population Capital     Area
#2       B  420000000  Landon 42100000

Answer 2

library(stringr)
library(tidyverse)
df2 <- df %>% 
  filter(!str_detect(Capital, "\/"))
#   Country Population Capital     Area
# 1       B  420000000  Landon 42100000

数据

df <- structure(list(Country = c("A", "B", "C", "D"), Population = c(210000210L,420000000L, 500000L, 520000100L), 
                     Capital = c("Sydney/Landon", "Landon", "Italy42/Rome1", "Dubai/Vienna21A"), 
                     Area = c(10000000L, 42100000L, 9200000L, 720000L)), class = "data.frame", row.names = c(NA,-4L))

如何在 R 中按名称模式删除行？

How to drop rows by name pattern in R?

regex

r