按 sku 分组,最大日期 SQL

Group by sku, max date SQL

我知道这里有很多人问这个问题,我尝试使用其他示例将其合并到我自己的示例中,但我似乎无法做到这一点。

我有 sku、日期和成本的列,我想查看所有 3 列,但只能按最大日期,按 sku 分组。 目前:

Sku   Date     Cost
1     06/24/15 .01
1     02/22/14 .02
2     06/24/15 .04
2     02/22/14 .05

需要:

Sku   Date     Cost
1     06/24/15 .01
2     06/24/15 .04

这是我的 SQL 的样子:

SELECT dbo_SKU.PROD_CODE AS Sku, dbo_LOTS.REC_DATE AS [Last Date], 
   dbo_LOT_ITEM.COST AS Cost
FROM (dbo_LOTS INNER JOIN dbo_SKU ON dbo_LOTS.SKU_ID = dbo_SKU.SKU_ID) 
INNER JOIN dbo_LOT_ITEM ON dbo_LOTS.LOT_ID = dbo_LOT_ITEM.LOT_ID;

这是设计视图的样子(我更喜欢视觉): Design View

这是自学如何操作 Access 以及它如何工作的第 2 周,所以如果我们能用蜡笔来解释我如何使它正确工作,那就太好了。

您可以添加额外的逻辑来获取最后日期。一种方法是在 WHERE 子句中添加相关子查询:

SELECT s.PROD_CODE AS Sku, l.REC_DATE AS [Last Date],  li.COST AS Cost
FROM (dbo_LOTS as l INNER JOIN
      dbo_SKU as si
      ON l.SKU_ID = s.SKU_ID
     ) INNER JOIN
     dbo_LOT_ITEM as li
     ON l.LOT_ID = li.LOT_ID
WHERE l.REC_DATE = (SELECT MAX(l2.REC_DATE)
                    FROM dbo_LOTS as l2
                    WHERE l2.SKU_ID = l.SKU_ID
                   );

这有效:

SELECT dbo_SKU.PROD_CODE AS Sku, dbo_LOTS.REC_DATE AS [Last Date], dbo_LOTS.COSTPERSKU AS Cost
FROM dbo_LOTS INNER JOIN dbo_SKU ON dbo_LOTS.SKU_ID = dbo_SKU.SKU_ID
WHERE (((dbo_LOTS.REC_DATE)=(SELECT MAX(l2.REC_DATE) 

FROM dbo_LOTS as l2 WHERE l2.SKU_ID = dbo_LOTS.SKU_ID)));