无法回显数组：只能打印它：并且只能回显特定数组

Question

<?php 
foreach ($recorded as $rows ) 
    {
        echo "<pre>";
        print_r ($rows); 
        echo "</pre>";

        echo "<img src='".base_url()."upload/thumbs/".$rows->file_name."'/>";
    } 
?>

当我打印 $rows 时，结果是：

Array
(
    [0] => stdClass Object
        (
            [file_name] => steve-big.jpg
        )

    [1] => stdClass Object
        (
            [file_name] => steve1-big.jpg
        )

    [2] => stdClass Object
        (
            [file_name] => steve2-big.jpg
        )

    [3] => stdClass Object
        (
            [file_name] => steve3-big.jpg
        )

)

Array
(
    [0] => stdClass Object
        (
            [file_name] => size-5-5-width-m.jpg
        )

    [1] => stdClass Object
        (
            [file_name] => 3316783.jpg
        )

    [2] => stdClass Object
        (
            [file_name] => 3316786.jpg
        )

    [3] => stdClass Object
        (
            [file_name] => 3316792.jpg
        )

)

但是为什么我不能回显呢？

我正在使用 codeIgniter，这是我收到的错误消息：

A PHP Error was encountered | Severity: Notice | Message: Trying to get property of non-object | Filename: views/mothershop.php | Line Number: 17

但是，如果我给它一个像这样的特定数字，我只能回应它：$rows[0]->file_name、$rows[1]，等等。

请帮忙，这真的让我很困惑。

Answer 1

检查错误：

A PHP Error was encountered | Severity: Notice | Message: Trying to get property of non-object | Filename: views/mothershop.php | Line Number: 17

因为$rows是一个数组，没有属性调用file_name。

Answer 2

我们可以看到 $rows 再次包含数组。所以你不能 echo 它。相反，您必须使用 print_r，到 echo 您必须迭代 $row 数组。试试下面的代码。

<?php 
foreach ($recorded as $rows ) 
    {
        // echo "<pre>";
        // print_r ($rows); 
        // echo "</pre>";
        foreach ($rows as $r) 
        {
            echo "<img src='".base_url()."upload/thumbs/".$r->file_name."'/>";
        } 
     }
?>

这可能对你有帮助。

Answer 3

尝试

<?php 
foreach ($recorded as $rows=>$val ) 
    {
       echo $val['file_name'].'<br/>';
    } 
?>

Answer 4

试试这个代码

<?php 
foreach ($recorded as $rows ) 
    {
        echo "<img src='".base_url()."upload/thumbs".$rows['file_name']."'/>";
    } 
?>

Answer 5

尝试在行上再次重申因为结果的数组结构是二维数组

foreach ($recorded as $rows ) {

    foreach ($rows as $key => $value) {
        echo "<img src='".base_url()."upload/thumbs/".$value->file_name."'/>";  
    }

}

Answer 6

这应该适合你：

foreach ($recorded as $rows) 
    array_walk($rows, function($v){
        echo "<img src='" . base_url() . "upload/thumbs/" . $v->file_name . "'/>";
    });

Answer 7

试试这个：

$baseUrl = base_url();
foreach ($recorded as &$rows) {
    foreach ($rows as &$row) {
        echo '<img src="'.$baseUrl.'upload/thumbs/'.$row->file_name.'"/>';
    } 
}

无法回显数组：只能打印它：并且只能回显特定数组

can't echo the array: only able to print it: and only echo the specific array

php

arrays

codeigniter

无法回显数组：只能打印它：并且只​​能回显特定数组

can't echo the array: only able to print it: and only echo the specific array

php

arrays

codeigniter

无法回显数组：只能打印它：并且只能回显特定数组