SQL

Question

当我执行 SQL 查询时，我得到下一个：

select  Item.No_, Entry.Quantity, MinMax.MaxQuantity, Entry.Location, Item.MainLocation
FROM Item
join Entry
on Item.No_ = Entry.[Item No_]
join MinMax
on Item.No_ = MinMax.Item No_

如果 MainLocation 的 Quantity 是 30，我想在另一个位置将 Quantity 填满到 MaxQuantity。这意味着

主要位置：A1 有 30 个数量，

但位置

A2 有 2 个

A3 有 12 个

A4 有 1 个

我想从 A1 中获取 MaxQuantity 的全部数量，然后我给 A2、A3、A4 并减少 A1。

我想接下来得到：

Answer 1

;with InitialQuery as 
(
    select  Item.No_, Entry.Quantity, MinMax.MaxQuantity, Entry.Location, Item.MainLocation
    from Item
    join Entry on Item.No_ = Entry.[Item No_]
    join MinMax on Item.No_ = MinMax.Item No_
)
, Sources as
(
    select * from InitialQuery
    where Location=MainLocation and Quantity=30
)
, Destinations as 
(
    select 
        i.*,
        i.MaxQuantity - i.Quantity 'Needed'
    from Sources s
    join InitialQuery i on i.No_=s.No_ and i.MainLocation=s.MainLocation and i.Location<>s.Location
)
select 
    s.No_,
    (s.Quantity - d.NoTransferred) 'Quantity',
    s.MaxQuantity,
    s.Location,
    s.MainLocation
from Sources s
join (
        select No_, MainLocation, sum(Needed) 'NoTransferred' from Destinations group by No_, MainLocation
    ) d on d.No_=s.No_ and d.MainLocation=s.MainLocation
union all
select 
    No_,
    MaxQuantity 'Quantity',
    MaxQuantity,
    Location,
    MainLocation
from Destinations

SQL - 如果或其他

SQL - if or something else

sql-server

ssms