要设置的数组不会截断 java 数组

Question

我正在将数组列表转换为 java 中的集合，但生成的集合没有产生预期的结果。

    String[] characterName = {"C","A","P","T","A","I","N","A","M","E","R","I","C","A"};
    String[] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
    List<String> pool = new ArrayList<String>();

    for(int i=0;i<characterName.length;i++) {
        pool.add(characterName[i]);
    }

    int difference = 19-characterName.length;

    for(int i=0;i<difference;i++) {
        pool.add(alphabet[i]);
    }

    Collections.shuffle(pool);
    Set<String> poolSet= new HashSet<>();
    poolSet.addAll(pool);

我已经对此进行了调试，但是当我将池中的所有内容添加到哈希集时，它只会添加数组的前 11 个字符。尽管当我调试时，它说 pool = 19，但它只加 11。我说错了吗？看起来很简单，但并不是全部相加。非常感谢任何输入。

Answer 1

java 中的

Set 要么包含项目，要么不包含。它们不包含它的多个副本。

在您的示例中，CAPTAINAMERICAABCDE 中只有 11 个唯一字符 CAPTINMERBD。这就是为什么你最后得到 11 的原因。

您可能希望使用 List，因为这样可以允许同一事物的多个实例。

要设置的数组不会截断 java 数组

Array to Set not cuts off java array

java

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hashset