在 Fortran 中实现匿名函数
Implementing anonymous functions in Fortran
这个问题是我上一个问题 的后续问题。在当前问题中,我简化了我的问题,这里是示例 MATLAB 代码。我想在 Fortran 中实现它。
%Script script1.m
clear vars;
close all;
clc;
fun1 = @(x1,x2) 3*x1^2 + 4*x2^2 + 5*x1 + 6*x2 + 10;
lower = -2;
upper = 0;
fun5 = fun15(fun1);
%fun5 is 'intermediate' function
%calling minimization function
[location,value]=minimize1(fun5,lower,upper)
在 script1.m 中,我创建了一个函数句柄 fun1
并希望为其赋值,如 fun15.m
中所示
%fun15.m
function fun2 = fun15( fun1 )
arr1 = [4,5];
arr2 = [-2,3];
fun2 = @(a) fun1( ( arr1(1) + a*arr2(1)) , ( arr1(2) + a*arr2(2)));
%fun2 = @(a) @(x4,y4,x5,y5) 3*(x4+a*x5)^2 + 4*(y4+a*y5)^2 + 5*(x4+a*x5) + 6*(y4+a*y5) + 10; .....(1)
end
而不是文件 fun15.m,很有可能创建如 (1) 所示的闭包。这里,arr1 = [x4,y4]
和 arr2=[x5,y5]
。我们可以先传递 x4,y4,x5,y5
的值,它会 return 变量 a
中的一个函数。这个 returned 函数被传递给下面的最小化函数。
%minimize1.m
function [loc,val] = minimize1 (fun1,lower,upper)
c1 = 1; %counter
x_1 = lower + (upper-lower)*0.382; %lower value
x_2 = lower + (upper-lower)*0.618; %upper value
f_1 = fun1(x_1); %fun1 is passed in the arguments
f_2 = fun1(x_2);
x_lower=lower;
x_upper=upper;
locx=0;
while c1<10
if (f_1 > f_2)
x_lower = x_1;
x_1=x_2;
f_1=f_2;
x_2 = x_lower + (x_upper-x_lower)*0.618;
f_2 = fun1(x_2);
else
x_upper = x_2;
x_2 = x_1;
f_2 = f_1;
x_1 = x_lower + (x_upper-x_lower)*0.382;
f_1 = fun1(x_1);
end
c1=c1+1;
end
locx=(x_lower + x_upper)/2.0;
val = fun1(locx);
end
如何将其转换为 Fortran - 尤其是函数 returning 函数? Anonymous Fortran 不支持函数(C++11 支持它作为 lambda,ALGOL 68 也支持)。是否可以在现代 Fortran (90,95,03,08) 中实现此问题?
Fortran 不支持匿名函数。简单的解决方法是编写一个具有名称的函数。
现代 Fortran 中有两种可能的方法来捕获函数所需的任何附加参数的值,超出被最小化的变量:
要最小化的过程表示为抽象类型(仿函数类型)的延迟绑定,底层函数的附加参数可用作抽象类型的具体扩展的组件。如有必要,组件之一可以是过程指针或仿函数类型的另一个对象。
要最小化的过程是一个内部(F2008)或模块过程,具有主机协会提供的附加参数。
什么是最好的取决于具体情况。
两种方法的示例如下。
MODULE Minimizer
IMPLICIT NONE
PRIVATE
INTEGER, PARAMETER, PUBLIC :: rk = KIND(1.0)
PUBLIC :: MinimizeFunctor
PUBLIC :: MinimizeProcedure
TYPE, PUBLIC, ABSTRACT :: Functor
CONTAINS
PROCEDURE(functor_Evaluate), DEFERRED :: Evaluate
END TYPE Functor
ABSTRACT INTERFACE
FUNCTION functor_Evaluate(obj, x)
IMPORT :: Functor
IMPORT :: rk
IMPLICIT NONE
CLASS(Functor), INTENT(IN) :: obj
REAL(rk), INTENT(IN) :: x
REAL(rk) :: functor_Evaluate
END FUNCTION functor_Evaluate
END INTERFACE
CONTAINS
SUBROUTINE MinimizeFunctor(fun, lower, upper, location, value)
CLASS(functor), INTENT(IN) :: fun
REAL(rk), INTENT(IN) :: lower
REAL(rk), INTENT(IN) :: upper
REAL(rk), INTENT(OUT) :: location
REAL(rk), INTENT(OUT) :: value
INTEGER :: c1
REAL(rk) :: x_1
REAL(rk) :: x_2
REAL(rk) :: f_1
REAL(rk) :: f_2
REAL(rk) :: x_lower
REAL(rk) :: x_upper
c1 = 1
x_lower = lower
x_upper = upper
f_1 = fun%Evaluate(x_1)
f_2 = fun%Evaluate(x_2)
location = 0
DO WHILE (c1 < 10)
IF (f_1 > f_2) THEN
x_lower = x_1
x_1 = x_2
f_1 = f_2
x_2 = x_lower + (x_upper - x_lower) * 0.618_rk
f_2 = fun%Evaluate(x_2)
ELSE
x_upper = x_2
x_2 = x_1
f_2 = f_1
x_1 = x_lower + (x_upper - x_lower) * 0.382_rk
f_1 = fun%Evaluate(x_1)
END IF
c1 = c1 + 1
END DO
location = (x_Lower + x_upper) / 2.0
value = fun%Evaluate(location)
END SUBROUTINE MinimizeFunctor
SUBROUTINE MinimizeProcedure(fun, lower, upper, location, value)
INTERFACE
FUNCTION fun(x)
IMPORT :: rk
IMPLICIT NONE
REAL(rk), INTENT(IN) :: x
REAL(rk) :: fun
END FUNCTION fun
END INTERFACE
REAL(rk), INTENT(IN) :: lower
REAL(rk), INTENT(IN) :: upper
REAL(rk), INTENT(OUT) :: location
REAL(rk), INTENT(OUT) :: value
INTEGER :: c1
REAL(rk) :: x_1
REAL(rk) :: x_2
REAL(rk) :: f_1
REAL(rk) :: f_2
REAL(rk) :: x_lower
REAL(rk) :: x_upper
c1 = 1
x_lower = lower
x_upper = upper
f_1 = fun(x_1)
f_2 = fun(x_2)
location = 0
DO WHILE (c1 < 10)
IF (f_1 > f_2) THEN
x_lower = x_1
x_1 = x_2
f_1 = f_2
x_2 = x_lower + (x_upper - x_lower) * 0.618_rk
f_2 = fun(x_2)
ELSE
x_upper = x_2
x_2 = x_1
f_2 = f_1
x_1 = x_lower + (x_upper - x_lower) * 0.382_rk
f_1 = fun(x_1)
END IF
c1 = c1 + 1
END DO
location = (x_Lower + x_upper) / 2.0
value = fun(location)
END SUBROUTINE MinimizeProcedure
END MODULE Minimizer
MODULE m
USE Minimizer
IMPLICIT NONE
PRIVATE
PUBLIC :: RunFunctor
PUBLIC :: RunProcedure
TYPE, EXTENDS(Functor) :: MyFunctor
PROCEDURE(fun_ptr_intf), POINTER, NOPASS :: fun_ptr
INTEGER :: arr1(2)
INTEGER :: arr2(2)
CONTAINS
PROCEDURE :: Evaluate
END TYPE MyFunctor
ABSTRACT INTERFACE
FUNCTION fun_ptr_intf(x1, x2)
IMPORT :: rk
IMPLICIT NONE
REAL(rk), INTENT(IN) :: x1
REAL(rk), INTENT(IN) :: x2
REAL(rk) :: fun_ptr_intf
END FUNCTION fun_ptr_intf
END INTERFACE
CONTAINS
FUNCTION Evaluate(obj, x)
CLASS(MyFunctor), INTENT(IN) :: obj
REAL(rk), INTENT(IN) :: x
REAL(rk) :: Evaluate
Evaluate = obj%fun_ptr( &
obj%arr1(1) + x * obj%arr2(1), &
obj%arr1(2) + x * obj%arr2(2) )
END FUNCTION Evaluate
FUNCTION fun1(x1, x2)
REAL(rk), INTENT(IN) :: x1
REAL(rk), INTENT(IN) :: x2
REAL(rk) :: fun1
fun1 = 3 * x1**2 + 4 * x2**2 + 5 * x1 + 6 * x2 + 10.0_rk
END FUNCTION fun1
SUBROUTINE RunFunctor
TYPE(MyFunctor) :: obj
REAL(rk) :: location
REAL(rk) :: value
obj%fun_ptr => fun1
obj%arr1 = [ 4, 5]
obj%arr2 = [-2, 3]
CALL MinimizeFunctor(obj, 0.0_rk, 1.0_rk, location, value)
PRINT *, location, value
END SUBROUTINE RunFunctor
SUBROUTINE RunProcedure
REAL(rk) :: location
REAL(rk) :: value
INTEGER :: arr1(2)
INTEGER :: arr2(2)
arr1 = [ 4, 5]
arr2 = [-2, 3]
CALL MinimizeProcedure(fun, 0.0_rk, 1.0_rk, location, value)
PRINT *, location, value
CONTAINS
FUNCTION fun(x)
REAL(rk), INTENT(IN) :: x
REAL(rk) :: fun
fun = fun1( &
arr1(1) + x * arr2(1), &
arr1(2) + x * arr2(2) )
END FUNCTION fun
END SUBROUTINE RunProcedure
END MODULE m
PROGRAM p
USE m
IMPLICIT NONE
CALL RunFunctor
CALL RunProcedure
END PROGRAM p
根据大众的要求,这不是 完全 的副本,因此我可以无耻地重复使用我以前的 material.
你问的是匿名函数,但你实际上想做的是将稍微修改过的函数传递给最小化过程。您通常不想为此模拟函数对象 (Fortran minimization of a function with additional arguments)
1。
传递此类过程的最简单方法是使用 内部过程 :
subroutine outer(fun1)
use minimization, only: minimize
interface
real function fun1(x,y)
real, intent(in) :: x, y
end function
end interface
real, dimension(2) :: arr1, arr2
arr1=...; arr2=...
call minimize(fun2)
contains
real function fun2(a)
real, intent(in) :: a
fun2 = fun1( ( arr1(1) + a*arr2(1)) , ( arr1(2) + a*arr2(2)))
end function
end subroutine
注意:传递内部过程和指向它们的指针需要 Fortran 2008。
- 您也可以对 模块过程 做同样的事情,我把它留作 reader 的练习,只需定义上下文(
arr1
, arr2
) 和最小化函数 fun2
不是在本地,而是在模块中。它不太灵活。
现在关闭:
即使在 C++98 中,您也可以使用 函数对象 或 函子 来存储函数指针的上下文以创建词法闭包。它只是一个 class ,它将捕获的上下文存储在其成员变量中。 C++11 除了为这样的 class.
提供语法糖外,没有做任何其他事情。
您可以在 Fortran 中创建仿函数,请参阅 Dynamic function creation from another function , Function as an output argument and Fortran - Return an anonymous function from subroutine,但我认为这对于您的目的来说太笨拙了。
这个问题是我上一个问题
%Script script1.m
clear vars;
close all;
clc;
fun1 = @(x1,x2) 3*x1^2 + 4*x2^2 + 5*x1 + 6*x2 + 10;
lower = -2;
upper = 0;
fun5 = fun15(fun1);
%fun5 is 'intermediate' function
%calling minimization function
[location,value]=minimize1(fun5,lower,upper)
在 script1.m 中,我创建了一个函数句柄 fun1
并希望为其赋值,如 fun15.m
%fun15.m
function fun2 = fun15( fun1 )
arr1 = [4,5];
arr2 = [-2,3];
fun2 = @(a) fun1( ( arr1(1) + a*arr2(1)) , ( arr1(2) + a*arr2(2)));
%fun2 = @(a) @(x4,y4,x5,y5) 3*(x4+a*x5)^2 + 4*(y4+a*y5)^2 + 5*(x4+a*x5) + 6*(y4+a*y5) + 10; .....(1)
end
而不是文件 fun15.m,很有可能创建如 (1) 所示的闭包。这里,arr1 = [x4,y4]
和 arr2=[x5,y5]
。我们可以先传递 x4,y4,x5,y5
的值,它会 return 变量 a
中的一个函数。这个 returned 函数被传递给下面的最小化函数。
%minimize1.m
function [loc,val] = minimize1 (fun1,lower,upper)
c1 = 1; %counter
x_1 = lower + (upper-lower)*0.382; %lower value
x_2 = lower + (upper-lower)*0.618; %upper value
f_1 = fun1(x_1); %fun1 is passed in the arguments
f_2 = fun1(x_2);
x_lower=lower;
x_upper=upper;
locx=0;
while c1<10
if (f_1 > f_2)
x_lower = x_1;
x_1=x_2;
f_1=f_2;
x_2 = x_lower + (x_upper-x_lower)*0.618;
f_2 = fun1(x_2);
else
x_upper = x_2;
x_2 = x_1;
f_2 = f_1;
x_1 = x_lower + (x_upper-x_lower)*0.382;
f_1 = fun1(x_1);
end
c1=c1+1;
end
locx=(x_lower + x_upper)/2.0;
val = fun1(locx);
end
如何将其转换为 Fortran - 尤其是函数 returning 函数? Anonymous Fortran 不支持函数(C++11 支持它作为 lambda,ALGOL 68 也支持)。是否可以在现代 Fortran (90,95,03,08) 中实现此问题?
Fortran 不支持匿名函数。简单的解决方法是编写一个具有名称的函数。
现代 Fortran 中有两种可能的方法来捕获函数所需的任何附加参数的值,超出被最小化的变量:
要最小化的过程表示为抽象类型(仿函数类型)的延迟绑定,底层函数的附加参数可用作抽象类型的具体扩展的组件。如有必要,组件之一可以是过程指针或仿函数类型的另一个对象。
要最小化的过程是一个内部(F2008)或模块过程,具有主机协会提供的附加参数。
什么是最好的取决于具体情况。
两种方法的示例如下。
MODULE Minimizer
IMPLICIT NONE
PRIVATE
INTEGER, PARAMETER, PUBLIC :: rk = KIND(1.0)
PUBLIC :: MinimizeFunctor
PUBLIC :: MinimizeProcedure
TYPE, PUBLIC, ABSTRACT :: Functor
CONTAINS
PROCEDURE(functor_Evaluate), DEFERRED :: Evaluate
END TYPE Functor
ABSTRACT INTERFACE
FUNCTION functor_Evaluate(obj, x)
IMPORT :: Functor
IMPORT :: rk
IMPLICIT NONE
CLASS(Functor), INTENT(IN) :: obj
REAL(rk), INTENT(IN) :: x
REAL(rk) :: functor_Evaluate
END FUNCTION functor_Evaluate
END INTERFACE
CONTAINS
SUBROUTINE MinimizeFunctor(fun, lower, upper, location, value)
CLASS(functor), INTENT(IN) :: fun
REAL(rk), INTENT(IN) :: lower
REAL(rk), INTENT(IN) :: upper
REAL(rk), INTENT(OUT) :: location
REAL(rk), INTENT(OUT) :: value
INTEGER :: c1
REAL(rk) :: x_1
REAL(rk) :: x_2
REAL(rk) :: f_1
REAL(rk) :: f_2
REAL(rk) :: x_lower
REAL(rk) :: x_upper
c1 = 1
x_lower = lower
x_upper = upper
f_1 = fun%Evaluate(x_1)
f_2 = fun%Evaluate(x_2)
location = 0
DO WHILE (c1 < 10)
IF (f_1 > f_2) THEN
x_lower = x_1
x_1 = x_2
f_1 = f_2
x_2 = x_lower + (x_upper - x_lower) * 0.618_rk
f_2 = fun%Evaluate(x_2)
ELSE
x_upper = x_2
x_2 = x_1
f_2 = f_1
x_1 = x_lower + (x_upper - x_lower) * 0.382_rk
f_1 = fun%Evaluate(x_1)
END IF
c1 = c1 + 1
END DO
location = (x_Lower + x_upper) / 2.0
value = fun%Evaluate(location)
END SUBROUTINE MinimizeFunctor
SUBROUTINE MinimizeProcedure(fun, lower, upper, location, value)
INTERFACE
FUNCTION fun(x)
IMPORT :: rk
IMPLICIT NONE
REAL(rk), INTENT(IN) :: x
REAL(rk) :: fun
END FUNCTION fun
END INTERFACE
REAL(rk), INTENT(IN) :: lower
REAL(rk), INTENT(IN) :: upper
REAL(rk), INTENT(OUT) :: location
REAL(rk), INTENT(OUT) :: value
INTEGER :: c1
REAL(rk) :: x_1
REAL(rk) :: x_2
REAL(rk) :: f_1
REAL(rk) :: f_2
REAL(rk) :: x_lower
REAL(rk) :: x_upper
c1 = 1
x_lower = lower
x_upper = upper
f_1 = fun(x_1)
f_2 = fun(x_2)
location = 0
DO WHILE (c1 < 10)
IF (f_1 > f_2) THEN
x_lower = x_1
x_1 = x_2
f_1 = f_2
x_2 = x_lower + (x_upper - x_lower) * 0.618_rk
f_2 = fun(x_2)
ELSE
x_upper = x_2
x_2 = x_1
f_2 = f_1
x_1 = x_lower + (x_upper - x_lower) * 0.382_rk
f_1 = fun(x_1)
END IF
c1 = c1 + 1
END DO
location = (x_Lower + x_upper) / 2.0
value = fun(location)
END SUBROUTINE MinimizeProcedure
END MODULE Minimizer
MODULE m
USE Minimizer
IMPLICIT NONE
PRIVATE
PUBLIC :: RunFunctor
PUBLIC :: RunProcedure
TYPE, EXTENDS(Functor) :: MyFunctor
PROCEDURE(fun_ptr_intf), POINTER, NOPASS :: fun_ptr
INTEGER :: arr1(2)
INTEGER :: arr2(2)
CONTAINS
PROCEDURE :: Evaluate
END TYPE MyFunctor
ABSTRACT INTERFACE
FUNCTION fun_ptr_intf(x1, x2)
IMPORT :: rk
IMPLICIT NONE
REAL(rk), INTENT(IN) :: x1
REAL(rk), INTENT(IN) :: x2
REAL(rk) :: fun_ptr_intf
END FUNCTION fun_ptr_intf
END INTERFACE
CONTAINS
FUNCTION Evaluate(obj, x)
CLASS(MyFunctor), INTENT(IN) :: obj
REAL(rk), INTENT(IN) :: x
REAL(rk) :: Evaluate
Evaluate = obj%fun_ptr( &
obj%arr1(1) + x * obj%arr2(1), &
obj%arr1(2) + x * obj%arr2(2) )
END FUNCTION Evaluate
FUNCTION fun1(x1, x2)
REAL(rk), INTENT(IN) :: x1
REAL(rk), INTENT(IN) :: x2
REAL(rk) :: fun1
fun1 = 3 * x1**2 + 4 * x2**2 + 5 * x1 + 6 * x2 + 10.0_rk
END FUNCTION fun1
SUBROUTINE RunFunctor
TYPE(MyFunctor) :: obj
REAL(rk) :: location
REAL(rk) :: value
obj%fun_ptr => fun1
obj%arr1 = [ 4, 5]
obj%arr2 = [-2, 3]
CALL MinimizeFunctor(obj, 0.0_rk, 1.0_rk, location, value)
PRINT *, location, value
END SUBROUTINE RunFunctor
SUBROUTINE RunProcedure
REAL(rk) :: location
REAL(rk) :: value
INTEGER :: arr1(2)
INTEGER :: arr2(2)
arr1 = [ 4, 5]
arr2 = [-2, 3]
CALL MinimizeProcedure(fun, 0.0_rk, 1.0_rk, location, value)
PRINT *, location, value
CONTAINS
FUNCTION fun(x)
REAL(rk), INTENT(IN) :: x
REAL(rk) :: fun
fun = fun1( &
arr1(1) + x * arr2(1), &
arr1(2) + x * arr2(2) )
END FUNCTION fun
END SUBROUTINE RunProcedure
END MODULE m
PROGRAM p
USE m
IMPLICIT NONE
CALL RunFunctor
CALL RunProcedure
END PROGRAM p
根据大众的要求,这不是 完全 的副本,因此我可以无耻地重复使用我以前的 material.
你问的是匿名函数,但你实际上想做的是将稍微修改过的函数传递给最小化过程。您通常不想为此模拟函数对象 (Fortran minimization of a function with additional arguments)
1。 传递此类过程的最简单方法是使用 内部过程 :
subroutine outer(fun1)
use minimization, only: minimize
interface
real function fun1(x,y)
real, intent(in) :: x, y
end function
end interface
real, dimension(2) :: arr1, arr2
arr1=...; arr2=...
call minimize(fun2)
contains
real function fun2(a)
real, intent(in) :: a
fun2 = fun1( ( arr1(1) + a*arr2(1)) , ( arr1(2) + a*arr2(2)))
end function
end subroutine
注意:传递内部过程和指向它们的指针需要 Fortran 2008。
- 您也可以对 模块过程 做同样的事情,我把它留作 reader 的练习,只需定义上下文(
arr1
,arr2
) 和最小化函数fun2
不是在本地,而是在模块中。它不太灵活。
现在关闭:
即使在 C++98 中,您也可以使用 函数对象 或 函子 来存储函数指针的上下文以创建词法闭包。它只是一个 class ,它将捕获的上下文存储在其成员变量中。 C++11 除了为这样的 class.
提供语法糖外,没有做任何其他事情。您可以在 Fortran 中创建仿函数,请参阅 Dynamic function creation from another function , Function as an output argument and Fortran - Return an anonymous function from subroutine,但我认为这对于您的目的来说太笨拙了。