无法腌制 scipy.spatial.KDTree 个对象

Question

我有一个代码，我在其中构建了一棵巨大的树，我需要保存它以备后用。不幸的是，我似乎无法腌制 scipy.spatial.KDTree 个对象。

事实上，当我运行这个：

import pickle
import scipy.spatial
tree=scipy.spatial.KDTree([[1,2,3]])
pickle.dump(tree,open('tree.p','wb'))

我收到错误：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python2.7/pickle.py", line 1370, in dump
    Pickler(file, protocol).dump(obj)
  File "/usr/lib64/python2.7/pickle.py", line 224, in dump
    self.save(obj)
  File "/usr/lib64/python2.7/pickle.py", line 331, in save
    self.save_reduce(obj=obj, *rv)
  File "/usr/lib64/python2.7/pickle.py", line 419, in save_reduce
    save(state)
  File "/usr/lib64/python2.7/pickle.py", line 286, in save
    f(self, obj) # Call unbound method with explicit self
  File "/usr/lib64/python2.7/pickle.py", line 649, in save_dict
    self._batch_setitems(obj.iteritems())
  File "/usr/lib64/python2.7/pickle.py", line 663, in _batch_setitems
    save(v)
  File "/usr/lib64/python2.7/pickle.py", line 331, in save
    self.save_reduce(obj=obj, *rv)
  File "/usr/lib64/python2.7/pickle.py", line 401, in save_reduce
    save(args)
  File "/usr/lib64/python2.7/pickle.py", line 286, in save
    f(self, obj) # Call unbound method with explicit self
  File "/usr/lib64/python2.7/pickle.py", line 562, in save_tuple
    save(element)
  File "/usr/lib64/python2.7/pickle.py", line 286, in save
    f(self, obj) # Call unbound method with explicit self
  File "/usr/lib64/python2.7/pickle.py", line 748, in save_global
    (obj, module, name))     pickle.PicklingError: Can't pickle <class 'scipy.spatial.kdtree.leafnode'>: it's not found as scipy.spatial.kdtree.leafnode

鉴于此，有没有办法腌制它？或者至少保存可用于快速重建树的对象的一部分？不然除了scipy.spatial.KDTree还有其他快速选项吗？

Answer 1

使用cKDTree代替KDTree如下：

import pickle
import scipy.spatial
tree=scipy.spatial.cKDTree([[1,2,3]])
pickle.dump(tree,open('tree.p','wb'))

无法腌制 scipy.spatial.KDTree 个对象

unable to pickle scipy.spatial.KDTree objects

python

pickle

scipy