Laravel 5 获得过去 30 天记录的条件
Laravel 5 where condition to get pass 30 days worth of records
我在实例 table 中有一个日期列,其 varchar 数据类型存储为 d-m-Y。在我的 where 条件下,我试图仅获取过去 30 天的记录。
$backdate = Carbon::parse('-30 days')->toDateString();
$date30DaysBack = Carbon::parse($backdate)->format('d-m-Y');
$adverts = DB::table('adverts')
->where(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), '>=',$date30DaysBack)
完整查询
$adverts = DB::table('adverts')
->select(DB::raw('(SELECT IF(ext = \'jpeg\', CONCAT(fullpath, \'_1.\', ext), (CONCAT(fullpath,\'.\',ext))) as fullpath FROM advertsstorage where uid_dir = adverts.ad_uid ORDER BY id ASC limit 1)as fullpath, adverts.*, domains.location,instances.date'))
->join('domains','adverts.domain', '=' ,'domains.domain')
->join('advertiser_domains','domains.id', '=' ,'advertiser_domains.domain_id')
->join('advertisers','advertiser_domains.advertiser_id', '=' ,'advertisers.u_id')
->join('instances','adverts.ad_uid','=','instances.ad_uid')
->join('urls','instances.u_id','=','urls.id')
->join('sites','urls.sites_id','=','sites.id')
->where('advertisers.u_id', '=',$advertiserID)
->where(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), '>=',Carbon::now()->subDays(30)->format('d-m-Y'))
->orderBy(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), 'DESC')
->get();
试试这个。
Carbon 有 subDays 函数,你可以通过它获取过去 30 天的数据
$date30DaysBack= Carbon::now()->subDays(30)->format('d-m-Y');
$today = Carbon::now()->format('d-m-Y');
$adverts = DB::table('adverts')
->whereBetween(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'),[$date30DaysBack,$today])->get()
你看过Carbon docs了吗?
您可以为此使用减法修饰符; Carbon::now()->subDays(30);
.
在您的代码中看起来像这样:
$adverts = DB::table('adverts')->where(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), '>=', Carbon::now()->subDays(30)->format('d-m-Y'))
你试过了吗DATEDIFF
method
$adverts = DB::table('adverts')
->select(DB::raw('(SELECT IF(ext = \'jpeg\', CONCAT(fullpath, \'_1.\', ext), (CONCAT(fullpath,\'.\',ext))) as fullpath FROM advertsstorage where uid_dir = adverts.ad_uid ORDER BY id ASC limit 1)as fullpath, adverts.*, domains.location,instances.date'))
->join('domains','adverts.domain', '=' ,'domains.domain')
->join('advertiser_domains','domains.id', '=' ,'advertiser_domains.domain_id')
->join('advertisers','advertiser_domains.advertiser_id', '=' ,'advertisers.u_id')
->join('instances','adverts.ad_uid','=','instances.ad_uid')
->join('urls','instances.u_id','=','urls.id')
->join('sites','urls.sites_id','=','sites.id')
->where('advertisers.u_id', '=',$advertiserID)
->where(DB::raw('DATEDIFF( now(), STR_TO_DATE(instances.date,"%d-%m-%Y") )'), '<=', 30)
->orderBy(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), 'DESC')
->get();
我在实例 table 中有一个日期列,其 varchar 数据类型存储为 d-m-Y。在我的 where 条件下,我试图仅获取过去 30 天的记录。
$backdate = Carbon::parse('-30 days')->toDateString();
$date30DaysBack = Carbon::parse($backdate)->format('d-m-Y');
$adverts = DB::table('adverts')
->where(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), '>=',$date30DaysBack)
完整查询
$adverts = DB::table('adverts')
->select(DB::raw('(SELECT IF(ext = \'jpeg\', CONCAT(fullpath, \'_1.\', ext), (CONCAT(fullpath,\'.\',ext))) as fullpath FROM advertsstorage where uid_dir = adverts.ad_uid ORDER BY id ASC limit 1)as fullpath, adverts.*, domains.location,instances.date'))
->join('domains','adverts.domain', '=' ,'domains.domain')
->join('advertiser_domains','domains.id', '=' ,'advertiser_domains.domain_id')
->join('advertisers','advertiser_domains.advertiser_id', '=' ,'advertisers.u_id')
->join('instances','adverts.ad_uid','=','instances.ad_uid')
->join('urls','instances.u_id','=','urls.id')
->join('sites','urls.sites_id','=','sites.id')
->where('advertisers.u_id', '=',$advertiserID)
->where(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), '>=',Carbon::now()->subDays(30)->format('d-m-Y'))
->orderBy(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), 'DESC')
->get();
试试这个。 Carbon 有 subDays 函数,你可以通过它获取过去 30 天的数据
$date30DaysBack= Carbon::now()->subDays(30)->format('d-m-Y');
$today = Carbon::now()->format('d-m-Y');
$adverts = DB::table('adverts')
->whereBetween(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'),[$date30DaysBack,$today])->get()
你看过Carbon docs了吗?
您可以为此使用减法修饰符; Carbon::now()->subDays(30);
.
在您的代码中看起来像这样:
$adverts = DB::table('adverts')->where(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), '>=', Carbon::now()->subDays(30)->format('d-m-Y'))
你试过了吗DATEDIFF
method
$adverts = DB::table('adverts')
->select(DB::raw('(SELECT IF(ext = \'jpeg\', CONCAT(fullpath, \'_1.\', ext), (CONCAT(fullpath,\'.\',ext))) as fullpath FROM advertsstorage where uid_dir = adverts.ad_uid ORDER BY id ASC limit 1)as fullpath, adverts.*, domains.location,instances.date'))
->join('domains','adverts.domain', '=' ,'domains.domain')
->join('advertiser_domains','domains.id', '=' ,'advertiser_domains.domain_id')
->join('advertisers','advertiser_domains.advertiser_id', '=' ,'advertisers.u_id')
->join('instances','adverts.ad_uid','=','instances.ad_uid')
->join('urls','instances.u_id','=','urls.id')
->join('sites','urls.sites_id','=','sites.id')
->where('advertisers.u_id', '=',$advertiserID)
->where(DB::raw('DATEDIFF( now(), STR_TO_DATE(instances.date,"%d-%m-%Y") )'), '<=', 30)
->orderBy(DB::raw('STR_TO_DATE(instances.date,"%d-%m-%Y")'), 'DESC')
->get();