如何在--safe-updates模式下删除最新的一些记录

Question

例如我要删除下面最近的三个记录 table

root@localhost:[test]10:14:02>select * from delete_test order by create_time desc;
+----+------+---------------------+
| id | code | create_time         |
+----+------+---------------------+
|  9 | fff  | 2016-06-18 10:08:28 |
|  8 | eee  | 2016-06-18 10:08:21 |
|  7 | ddd  | 2016-06-18 10:08:15 |
|  3 | ccc  | 2016-06-17 22:18:48 |
|  2 | bbb  | 2016-06-17 22:18:42 |
|  1 | aaa  | 2016-06-17 22:18:37 |
+----+------+---------------------+

首先我尝试了

root@localhost:[test]10:14:14>delete from delete_test where code in (select code from delete_test order by create_time desc limit 3);
ERROR 1235 (42000): This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'

然后我试了

root@localhost:[test]10:17:05>delete a from delete_test a, (select code from delete_test order by create_time desc limit 3) b where a.code = b.code;
ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column

但 code 提交的是 unique key。

然后我尝试了

root@localhost:[test]10:18:49>delete a from delete_test a join (select code from delete_test order by create_time desc limit 3) b on a.code = b.code where a.id>0;
ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column

但我明确地使用了 primary key。

所以我想知道如何在--safe-updates模式下删除最近的一些记录？

Answer 1

您可以像这样简单地做：

delete from delete_test order by create_time limit 3;

看到它在这里工作：http://sqlfiddle.com/#!9/04f68/1

如果我没有按正确的顺序排列，只需将 order by 部分更改为 order by create_time desc

如何在--safe-updates模式下删除最新的一些记录

how to delete the latest some records in --safe-updates mode

mysql

sql-delete