jOOQ

Question

在我的数据库中我有一个 table:

CREATE TABLE calibration_factor_pm1
(
sensor_id Integer REFERENCES sensor(id),
factor_a double precision NOT NULL,
factor_b double precision NOT NULL,
time_from_which_factor_is_used timestamp NOT NULL
)

并且由于还有其他一些 table 像这个我想创建一个函数，我可以将有关我想获取的因素（a 或 b）以及从中获取的信息传递给

=29=].

我尝试这样做：

private Double getCalibrationFactor(String sensorId, TableField<Record, TableImpl> factor, TableImpl PM, TableField<Record, TableImpl> sensorIdTableField, TableField<Record, TableImpl> timeFromWhichFactorIsUsed) {
        Double calibrationFactorAPM1 = 1.0;
        try {
            calibrationFactorAPM1 = Double.valueOf(Database.create
                    .select(factor) //CalibrationFactorPm1.CALIBRATION_FACTOR_PM1.FACTOR_A
                    .from(PM) //CalibrationFactorPm1.CALIBRATION_FACTOR_PM1
                    .where(sensorIdTableField.equal(Integer.valueOf(sensorId)))
                    .orderBy(timeFromWhichFactorIsUsed.desc())
                    .fetchOne()
                    .getValue(0)
                    .toString());
        } catch (NullPointerException e) {
            System.out.println("DEBUG: Can't find calibration factor 'a' for this sensor");
            e.printStackTrace();
        }
    }

但是，我在 .where(sensorIdTableField.equal(Integer.valueOf(sensorId))) 行得到 Cannot resolve method 'equal(java.lang.Integer)'。

如何正确处理这个问题？

@edit

这就是 equal() 所期望的：

Answer 1

我建议在您的方法签名中使用更多抽象类型，特别是因为您似乎知道传递给您的方法的参数的类型。这样您就可以从 jooq 的类型安全功能中受益。

private Double getCalibrationFactor(String sensorId,
                                    Field<Double> factor,
                                    Table<?> PM,
                                    Field<Integer> sensorIdTableField,
                                    Field<Timestamp> timeFromWhichFactorIsUsed) {
  Record1<Double> calibrationFactorAPM1 = Database.create
              .select(factor) //CalibrationFactorPm1.CALIBRATION_FACTOR_PM1.FACTOR_A
              .from(PM) //CalibrationFactorPm1.CALIBRATION_FACTOR_PM1
              .where(sensorIdTableField.equal(Integer.valueOf(sensorId)))
              .orderBy(timeFromWhichFactorIsUsed.desc())
              .fetchOne();
  return calibrationFactorAPM1 == null ? calibrationFactorAPM1.value1() : 1d;
}

您可能还想传递 Integer sensorId 而不是 String sensorId。

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function