Batch error: Numeric constants are either decimal (17), hexadecimal (0x11), or octal (021)
Batch error: Numeric constants are either decimal (17), hexadecimal (0x11), or octal (021)
我正在提取两位数字并在其中加一。但是当最后两位数字是 08 时，就会抛出上述错误。
set last_two=!file_name:~-2,2!
set /a add_millisec=!last_two!+1
set add_millisec=0!add_millisec!
set add_millisec=!add_millisec:~-2!
有人可以检查并帮助我吗...
打开命令提示符 window 并键入 set /?:
[...] Numeric values are decimal numbers, unless prefixed by 0x for hexadecimal numbers, and 0 for octal numbers. So 0x12 is the same as 18 is the same as 022. Please note that the octal notation can be confusing: 08 and 09 are not valid numbers because 8 and 9 are not valid octal digits. [...]
您会发现 set /A 将带前导 0 的数字视为八进制数。
要克服这个问题，您可以执行以下操作：
在数字前面加上1，计算完再去掉：
set last_two=1!file_name:~-2,2!
set /A add_millisec=last_two+1
set add_millisec=!add_millisec:~-2!
为此你需要提前知道总位数。
在任何计算之前删除尾随零，然后根据需要用前导零填充结果：
set last_two=!file_name:~-2,2!
rem The following line removes all leading zeros:
for /F "tokens=* delims=0" %%Z in ("!last_two!") do set last_two=%%Z
set /A last_two+=0 & rem this avoids `last_two` to be empty if it is `0`
set /A add_millisec=last_two+1
set add_millisec=0!add_millisec!
set add_millisec=!add_millisec:~-2!
或者：
set last_two=!file_name:~-2,2!
rem The following two lines remove all leading zeros:
cmd /C exit !last_two!
set /A last_two=!ErrorLevel!
set /A add_millisec=last_two+1
set add_millisec=0!add_millisec!
set add_millisec=!add_millisec:~-2!
这种方法比较灵活，因为你不知道位数。
我正在提取两位数字并在其中加一。但是当最后两位数字是 08 时，就会抛出上述错误。
set last_two=!file_name:~-2,2!
set /a add_millisec=!last_two!+1
set add_millisec=0!add_millisec!
set add_millisec=!add_millisec:~-2!
有人可以检查并帮助我吗...
打开命令提示符 window 并键入 set /?:
[...] Numeric values are decimal numbers, unless prefixed by 0x for hexadecimal numbers, and 0 for octal numbers. So 0x12 is the same as 18 is the same as 022. Please note that the octal notation can be confusing: 08 and 09 are not valid numbers because 8 and 9 are not valid octal digits. [...]
您会发现 set /A 将带前导 0 的数字视为八进制数。
要克服这个问题，您可以执行以下操作：
在数字前面加上
1，计算完再去掉：set last_two=1!file_name:~-2,2! set /A add_millisec=last_two+1 set add_millisec=!add_millisec:~-2!为此你需要提前知道总位数。
在任何计算之前删除尾随零，然后根据需要用前导零填充结果：
set last_two=!file_name:~-2,2! rem The following line removes all leading zeros: for /F "tokens=* delims=0" %%Z in ("!last_two!") do set last_two=%%Z set /A last_two+=0 & rem this avoids `last_two` to be empty if it is `0` set /A add_millisec=last_two+1 set add_millisec=0!add_millisec! set add_millisec=!add_millisec:~-2!或者：
set last_two=!file_name:~-2,2! rem The following two lines remove all leading zeros: cmd /C exit !last_two! set /A last_two=!ErrorLevel! set /A add_millisec=last_two+1 set add_millisec=0!add_millisec! set add_millisec=!add_millisec:~-2!这种方法比较灵活，因为你不知道位数。