如何从 QThread 为 2 个类发出相同的信号

Question

我想这样做：有一个叫做 'Main' 的 class。还有一个 class 叫做 'aClass'。还有第三个 class 称为 'Thread'。这是我们的线程 class。 'Main' 是我们的主要 class，我们从 Main class 开始我们的线程 class。当我们的线程 class 启动时，它会从运行() 函数发出信号... 'Main' 和 'aClass' class 试图捕捉这些信号。 'Main' class 能够捕获从线程 class 发出的信号，但是 'aClass' 无法捕获相同的信号，因为我没有从 [=30 启动 QThread =].我只定义在'aClass'.

代码如下：

#!/usr/bin/env python

from PyQt4.QtGui import *
from PyQt4.QtCore import *
import sys


class Main(QMainWindow):
    def __init__(self):
        QMainWindow.__init__(self)

        self.setWindowTitle("Test")
        self.aClass = aClass()

        self.thread = Thread()
        self.thread.printMessage.connect(self.write)
        self.initUI()

    def initUI(self):
        self.button = QPushButton("Start Process", self)
        self.button.clicked.connect(self.startProcess)

    def startProcess(self):
        self.thread.start()

    def terminateProcess(self):
        self.thread.terminate()

    def write(self):
        print "Main: hello world..."


class aClass(object):
    def __init__(self):
        print "aClass: I have been started..."
        self.thread = Thread()
        self.thread.printMessage.connect(self.write)

    def write(self):
        print "aClass: hello world..."

class Thread(QThread):
    printMessage = pyqtSignal()

    def __init__(self):
        QThread.__init__(self)
        print "Thread: I have been started..."

    def run(self):

        self.printMessage.emit()
        print "Thread: I emitted the message."

if __name__ == "__main__":
    app = QApplication(sys.argv)
    root = Main()
    root.show()
    app.exec_()

结果：程序启动时，输出为：

aClass: I have been started... 
Thread: I have been started...
Thread: I have been started...

当我点击 'Start Process' 按钮时，输出是：

Thread: I emitted the message.
Main: hello world...

总产量：

aClass: I have been started...
Thread: I have been started...
Thread: I have been started...
Thread: I emitted the message.
Main: hello world...

点击'Start Process'想要得到的输出：

Thread: I emitted the message.
Main: hello world...
aClass: hello world...

我想要这个结果，但我不想使用 'aClass' 中的 self.thread.start() 命令，因为我只想运行线程一次...

Answer 1

您正在做的是在 aClass 对象中创建第二个 Thread，它与 Main 中的 Thread 不同。您需要将 Main 中 self.thread 的信号连接到 self.aClass 对象中的插槽 write。

您想这样做：

class Main(QMainWindow):
    def __init__(self):
        QMainWindow.__init__(self)

        self.setWindowTitle("Test")
        self.aClass = aClass()

        self.thread = Thread()
        self.thread.printMessage.connect(self.write)
        self.thread.printMessage.connect(self.aClass.write)


...

class aClass(object):
    def __init__(self):
        print "aClass: I have been started..."
        #self.thread = Thread() #This makes a new Thread
        #self.thread.printMessage.connect(self.write)

    def write(self):
        print "aClass: hello world..."
        self.initUI()

如何从 QThread 为 2 个类发出相同的信号

How to emit same signal for 2 classess from QThread

python

pyqt4

qthread