从该字符串格式中获取子字符串

Get substrings from that string format

我有以下数据,我可以有 3 种不同的情况:

案例 1:

"afield1" : "something1", "credentials" : [] , "afield2" : "something2" 

案例二:

"afield1" : "something1", "credentials" : [ ["root", "toor"] ] , "afield2" = "something2"

案例 3:

"afield1" : "something1", "credentials" : [ [ "admin", "support" ], [
"admin", "password" ], [ "admin", "123321" ] ] , "afield2" : "something2"

如何获取用户名和密码?

编辑:

我为第一种情况找到了一个愚蠢的方法..但其他情况非常简单..它不能在逗号 (,) 或小括号 ([ ]) 上展开...如果有人知道如何做,请帮助爆炸正确或从那个东西中获取值...

您可以像在这段代码中那样使用 preg_matchpreg_match_all 函数

$credentials = [];

$text = '"afield1" = "something1", "credentials" : [ [ "admin", "support" ], ["admin", "pass]word" ], [ "admin", "123321" ] ] , "afield2" = "something2"';

preg_match('/"credentials" : \[(.*?)\] ,/i', $text, $matches);
preg_match_all('/\[[ ]?"(.*?)"[ ]?\]/i', $matches[1], $matches2);

foreach ($matches2[1] as $match) {
    preg_match_all('/"(.*?)"/i', '"' . $match . '"', $matches3);

    $credential = ['login' => $matches3[1][0], 'password' => $matches3[1][1]];
    $credentials[] = $credential;
}

var_dump($credentials);

在输出中你可以看到

array(3) {
  [0]=>
  array(2) {
    ["login"]=>
    string(5) "admin"
    ["password"]=>
    string(7) "support"
  }
  [1]=>
  array(2) {
    ["login"]=>
    string(5) "admin"
    ["password"]=>
    string(8) "pass]word"
  }
  [2]=>
  array(2) {
    ["login"]=>
    string(5) "admin"
    ["password"]=>
    string(6) "123321"
  }
}

此代码适用于您问题中的其他示例。