如何从 javascript 对象中删除父键？

Question

我目前有这个对象：

schoolsObject = [{
  "college_1":
    {
      "id":"college_1",
      "location":"Victoria",
      "name":"College One"
    },
  "college_2":
    {
      "id":"college_2",
      "location":"Tasmania",
      "name":"College Two"
    }
  }];

我想删除顶级密钥，即。 college_1、college_2 和 'flatten' 对象是这样出来的，所以我没有 'top level' 键：

flatSchoolsObject = 
    [{
      "id":"college_1",
      "location":"Victoria",
      "name":"College One"
    },
    {
      "id":"college_2",
      "location":"Tasmania",
      "name":"College Two"
    }];

这是我最近的尝试，我做了很多不同的尝试，但没有记录下来：

// schoolIDs = Object.keys(schoolsObject);
var schools = {};

for(var i=0; i<Object.keys(schoolsObject).length; i++){
  for (var property in schoolsObject) {
    if (schoolsObject.hasOwnProperty(property)) {
      schools[i] = {
        'id': schoolsObject[property]['id'],
        'name' : schoolsObject[property]['name'],
        'location': schoolsObject[property]['location'],
      };
    }
  }
}
console.log(schools)

显然这不是我想要的，因为它给我留下了 Object {0: Object, 1: Object}。

我想在这里做的是可能的还是我看错了？

Answer 1

您可以在 Object.keys 的结果上使用 Array#map 来完成它。由于数组中只有一个对象，我们这样做：

schoolsObject = Object.keys(schoolsObject[0]).map(function(key) {
  return schoolsObject[0][key];
});

实例：

var schoolsObject = [
  {
  "college_1": {
    "id": "college_1",
    "location": "Victoria",
    "name": "College One"
  },
  "college_2": {
    "id": "college_2",
    "location": "Tasmania",
    "name": "College Two"
  }
}];
schoolsObject = Object.keys(schoolsObject[0]).map(function(key) {
  return schoolsObject[0][key];
});
console.log(schoolsObject);

对于 ES2015+，您可以使用箭头函数来缩短它：

schoolsObject = Object.keys(schoolsObject[0]).map(key => schoolsObject[0][key]);

Answer 2

(Codewise) 最简单的解决方案可能是使用 Object.keys() and Array.map():

的组合

flatSchoolsObject = Object.keys( schoolsObject[0] )
                          .map( ( key ) => schoolsObject[0][ key ] );

如果schoolsObject数组有更多条目，代码将不得不稍微调整：

let step1 = schoolsObject.map( ( el ) => {
              return Object.keys( schoolsObject[0] )
                           .map( ( key ) => schoolsObject[0][ key ] );
            })
flatSchoolsObject = [].concat.apply( [], step1 );

（step1 变量只是为了便于阅读而引入的。）

Answer 3

您需要concat从schoolObject中的每个项目中提取值的结果

flatSchoolsObject  = [].concat.call(
    schoolsObject.map(function(item) {
       return Object.keys(item).map(function(key) {
          return item[key];
       })
    })    
)

或使用Array.prototype.reduce

flatSchoolsObject = schoolsObject.reduce(function(acc, item) {
  return acc.concat(Object.keys(item).map(function(key){
     return item[key]
  })
}, [])

Answer 4

// Code goes here
var schoolsObject = [{
  "college_1":
    {
      "id":"college_1",
      "location":"Victoria",
      "name":"College One"
    },
  "college_2":
    {
      "id":"college_2",
      "location":"Tasmania",
      "name":"College Two"
    }
  }];
  var result = Object.keys(schoolsObject[0]).map(function(key){
    return schoolsObject[0][key];
  })

console.log(result);

其他版本

var schoolsObject = [{
  "college_1": {
    "id": "college_1",
    "location": "Victoria",
    "name": "College One"
  },
  "college_2": {
    "id": "college_2",
    "location": "Tasmania",
    "name": "College Two"
  }
}];
var result = [];

for (var property in schoolsObject[0]) {
  if (schoolsObject[0].hasOwnProperty(property)) {
    result.push(schoolsObject[0][property]);
  }
}

console.log(result);

Answer 5

给定对象：

schoolsObject = [{
    "college_1":{
        "id":"college_1",
        "location":"Victoria",
        "name":"College One"
    },
    "college_2":{
        "id":"college_2",
        "location":"Tasmania",
        "name":"College Two"
    }
}];

解决方案：

Object.values(schoolsObject[0]);

结果：

[{
    "id":"college_1",
    "location":"Victoria",
    "name":"College One"
},{
    "id":"college_2",
    "location":"Tasmania",
    "name":"College Two"
}]

如何从 javascript 对象中删除父键？

How can I remove the parent keys from a javascript Object?

javascript

javascript-objects