如何编写基于 Django class 的视图来显示和提交来自其他模板的表单？

Question

我有一个 ModelForm，我想在多个地方显示。例如，在 ListView 中，在文章列表下方。我可以通过将它放在 ListView 的 get_context_data() 中来做到这一点。我还想在自己的模板中显示表单。

我已经为表单创建了一个视图，但不确定如何实际编写它。

我在我的模型中定义了一个get_absolute_url()：

class Article(models.Model):
    author = models.ForeignKey('auth.User')
    title = models.CharField(max_length=200)
    text = models.TextField()
    categories = models.ManyToManyField(Category)
    city = models.ForeignKey(City)

    def __str__(self):
        return self.title

    def get_absolute_url(self):
        return reverse_lazy('article', args=self.id)

表单本身的视图是：

Views.py

class ArticleSubmitView(CreateView):
    model = Article
    form_class = ArticleSubmitForm
    # is initial necessary?
    inital = {'title': '', 'text': '', 'categories': '', 'city': ''}
    # success url not necessary because model has get_absolute_url
    # however it does not redirect to the article
    template_name = 'articles/article-submit.html'
    # handle post data from other template/view
    # ???

模板包含表单（ListView 模板也一样）。

article-submit.html

{% extends 'articles/base.html' %}
{% block article-submit %}
    {% include 'articles/article-form.html' %}
{% endblock article-submit %}

表单提交到调用 CreateView 的 url：

article-form.html

<form action="{% url 'article-submit' %}" method="POST">
    {% csrf_token %}
    {% for field in form %}
    <!--- etc. --->
    {% endfor %}
</form>

urls.py

from django.conf.urls import url
from .views import ArticlesView, ArticleSubmitView

urlpatterns = [
    url(r'^$', ArticlesView.as_view(), name='articles'),
    # some urls left out for brevity
    url(r'^article-submit/$', ArticleSubmitView.as_view(), name='article-submit'),
]

但是，表单不从列表模板提交，也不从表单模板本身提交。它也不会重定向或显示任何错误消息。

我做错了什么？

Full code is available here.

编辑：

像这样检查表格是否有效表明表格实际上是无效的：

class ArticleSubmitView(CreateView):
    model = Article
    form_class = ArticleSubmitForm
    # success url not necessary because model has get_absolute_url
    # however it does not redirect to the article
    template_name = 'articles/article-submit.html'
    # handle post data from other template/view
    # ???
    def form_valid(self, form):
        print('form is valid')
    def form_invalid(self, form):
        print('form is invalid')
        print(form.errors)

然而我得到：
AttributeError at /article-submit/
'ArticleSubmitForm' object has no attribute 'errors'

将表单呈现为{{ form }}时会发生同样的事情

Answer 1

事实证明，我不需要 django-betterforms。常规模型形式工作得很好。还有其他一些错误。

这是代码。

models.py

class Article(models.Model):
    author = models.ForeignKey('auth.User')
    title = models.CharField(max_length=200)
    text = models.TextField()
    categories = models.ManyToManyField(Category)
    city = models.ForeignKey(City)

    def __str__(self):
        return self.title

    def get_absolute_url(self):
        return reverse_lazy('article', kwargs={'pk': self.id})

views.py

class ArticleSubmitView(CreateView):
    model = Article
    form_class = ArticleForm
    template_name = 'articles/article-submit.html'

    def form_valid(self, form):
        print('form is valid')
        print(form.data)
        obj = form.save(commit=False)
        obj.author = self.request.user
        obj.save()
        return HttpResponseRedirect(reverse('article', kwargs={'pk': obj.id}))

网址和模板（大部分）与上述相同。

如何编写基于 Django class 的视图来显示和提交来自其他模板的表单？

How to write Django class-based view for form displaying and submission from other template?

python

django

django-templates

django-forms

django-class-based-views