使用 PHP 创建 CSV 文件

Question

我想创建一个新的 .csv 文件（无需先通过 fopen 打开原始文件）。到目前为止我试过这个：

$list[] = array
(
    "Name" => "John",
    "Gender" => "M",
    "Age" => "21"
);
$timestamp0 = date("Y-m-d H:i:sa", time());
$datetime = new DateTime($timestamp0);
$datetime->setTimezone(new DateTimeZone('Asia/Jakarta'));
$timestamp = $datetime->format("Y-m-d_H-i");

$filename = __DIR__ . "/file/" . $timestamp . ".csv";

$header = array("name", "gender", "age");
file_put_contents($filename, implode("\n", $list)); // error here bcs array given :')

我的问题是：

How can I change array 2d to csv?

非常需要你的帮助:(非常感谢你:")

Answer 1

使用 fopen 和 w 将创建文件（如果不存在）：

$list = [
    ["Name" => "John", "Gender" => "M"],
    ["Name" => "Doe", "Gender" => "M"],
    ["Name" => "Sara", "Gender" => "F"]
];

$fp = fopen($filename, 'w');
//Write the header
fputcsv($fp, array_keys($list[0]));
//Write fields
foreach ($list as $fields) {
    fputcsv($fp, $fields);
}
fclose($fp);

如果您不喜欢 fputcsv 和 fopen，您可以使用以下替代方法：

$list = [
    ["Name" => "John", "Gender" => "M"],
    ["Name" => "Doe", "Gender" => "M"],
    ["Name" => "Sara", "Gender" => "F"]
];

$csvArray = ["header" => implode (",", array_keys($list[0]))] + array_map(function($item) {
    return implode (",", $item);
}, $list);

file_put_contents($filename, implode ("\n", $csvArray));

希望对您有所帮助。

Answer 2

您可以使用下面的代码

$list[]=array ("name","gender","age"); // push header here
$list[] = array("John","M","21"); // push record here

$timestamp0     = date("Y-m-d H:i:sa",time());
$datetime       = new DateTime($timestamp0);
$datetime->setTimezone(new DateTimeZone('Asia/Jakarta'));
$timestamp      = $datetime->format("Y-m-d_H-i");

$filename = __DIR__ . "/file/" . $timestamp . ".csv";

$fp = fopen($filename, 'w');
foreach ($list as $fields) {
    fputcsv($fp, $fields);
}
fclose($fp);

有关更多详细信息，请阅读有关 CSV 文件的 php 手册。 http://php.net/manual/en/function.fputcsv.php

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