Boost:spirit 解析为结构并重用其中的一部分
Boost:spirit Parsing into structure and reusing parts of it
我必须在句子中找到变量并用它们的值替换它们。变量可以写成不同的形式,例如 $varName 或 $(varName)。
我想要一个 struct VariableHolder 以便轻松访问两者:
struct VariableHolder
{
string name; // contains "varName"
string fromFile; // contains "$(varName)" or "$varName"
void setName(ustring n) { name = n; }
}
显然,我想避免进行多次传递并调用多个解析器。
到目前为止我所拥有的是:
BOOST_FUSION_ADAPT_STRUCT(VariableHolder,
(ustring, fromFile)
)
// variableName is another parser that returns a string
qi::rule<Iterator, VariableHolder()> variable %=
(qi::char_("$")
>> (variableName[phoenix::bind(&VariableHolder::setName, qi::_val, qi::_1)]
| (qi::char_("(")
>> variableName[phoenix::bind(&VariableHolder::setName, qi::_val, qi::_1)]
>> qi::char_(")")))
);
这是行不通的。名称设置正确,但 fromFile 变量只包含一个“$”,没有任何其他内容。
所以,我想问你们这些好人:
- 我的想法是只用 BOOST_FUSION_ADAPT_STRUCT 调整部分结构,并用语义动作填充其余部分。愚蠢的想法,还是我做错了?
有没有一种方法可以绑定语义操作并仍然获得输出?喜欢
char_[doSomething] // 这可以同时调用 doSomething 并解析一个字符吗?
解决问题:
- My idea was to only adapt part of the structure with
BOOST_FUSION_ADAPT_STRUCT
, and fill the rest with semantic actions. Stupid idea, or am I just doing it wrong?
并非不可想象。不是我的推荐(参见 Boost Spirit: "Semantic actions are evil"?)。但是,是的,你做错了:
如果您不希望它成为公开属性的一部分,您需要 lit("$")
而不是 char_("$")
。其实'$'
这里就可以了
Is there a way to bind a semantic action and still get the output? Like
char_[doSomething] // Can this both call doSomething, and parse a char?
是的。您现在正在这样做,并且它之所以有效,是因为您使用了 operator%=
而不是 operator=
(请参阅文档:http://www.boost.org/doc/libs/1_61_0/libs/spirit/doc/html/spirit/qi/reference/nonterminal/rule.html#spirit.qi.reference.nonterminal.rule.expression_semantics)。
但是,您似乎真的在尝试使用相同的输入两次(原始为 fromFile
和 "cooked" 为 name
?)适得其反,因为自动规则属性propagation also 用你想要的值覆盖 name
fromFile
.
这里唯一快速的出路是只使用 SA。不过,我建议让 VariableHolder
的构造函数负责细节。
Side note: it looks a bit as if the optional parentheses suggest an expression grammar. If so, make that explicit in the grammar, instead of hardcoding a special case in the rule for a variableName
. If not, carry on :)
这是一个尝试修复:
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
namespace qi = boost::spirit::qi;
namespace phoenix = boost::phoenix;
struct VariableHolder {
std::string name; // contains "varName"
std::string fromFile; // contains "$(varName)" or "$varName"
};
template <typename It, typename Skipper = qi::ascii::space_type> struct P : qi::grammar<It, VariableHolder(), Skipper> {
P() : P::base_type(start) {
auto _name = phoenix::bind(&VariableHolder::name, qi::_val);
auto _fromFile = phoenix::bind(&VariableHolder::fromFile, qi::_val);
variableName = qi::alpha >> +qi::alnum;
variable = '$' >> (variableName | '(' >> variableName >> ')');
start = qi::as_string [ qi::raw [
variable [ _name = qi::_1 ]]
] [ _fromFile = qi::_1 ];
BOOST_SPIRIT_DEBUG_NODES((start)(variable)(variableName))
}
private:
qi::rule<It, std::string(), Skipper> variable;
qi::rule<It, VariableHolder(), Skipper> start;
// lexemes
qi::rule<It, std::string()> variableName;
};
int main() {
using It = std::string::const_iterator;
P<It> const p;
for (std::string const input : {
"$foo1",
"$(bar2)"
})
{
It f = input.begin(), l = input.end();
VariableHolder data;
bool ok = qi::phrase_parse(f, l, p, qi::ascii::space, data);
if (ok) {
std::cout << "Parse success: " << data.name << " (source: '" << data.fromFile << "')\n";
} else {
std::cout << "Parse failure ('" << input << "')\n";
}
if (f != l) {
std::cout << "Remaining unparsed input: '" << std::string(f, l) << "'\n";
}
}
}
版画
Parse success: foo1 (source: '$foo1')
Parse success: bar2 (source: '$(bar2)')
我必须在句子中找到变量并用它们的值替换它们。变量可以写成不同的形式,例如 $varName 或 $(varName)。
我想要一个 struct VariableHolder 以便轻松访问两者:
struct VariableHolder
{
string name; // contains "varName"
string fromFile; // contains "$(varName)" or "$varName"
void setName(ustring n) { name = n; }
}
显然,我想避免进行多次传递并调用多个解析器。 到目前为止我所拥有的是:
BOOST_FUSION_ADAPT_STRUCT(VariableHolder,
(ustring, fromFile)
)
// variableName is another parser that returns a string
qi::rule<Iterator, VariableHolder()> variable %=
(qi::char_("$")
>> (variableName[phoenix::bind(&VariableHolder::setName, qi::_val, qi::_1)]
| (qi::char_("(")
>> variableName[phoenix::bind(&VariableHolder::setName, qi::_val, qi::_1)]
>> qi::char_(")")))
);
这是行不通的。名称设置正确,但 fromFile 变量只包含一个“$”,没有任何其他内容。
所以,我想问你们这些好人:
- 我的想法是只用 BOOST_FUSION_ADAPT_STRUCT 调整部分结构,并用语义动作填充其余部分。愚蠢的想法,还是我做错了?
有没有一种方法可以绑定语义操作并仍然获得输出?喜欢
char_[doSomething] // 这可以同时调用 doSomething 并解析一个字符吗?
解决问题:
- My idea was to only adapt part of the structure with
BOOST_FUSION_ADAPT_STRUCT
, and fill the rest with semantic actions. Stupid idea, or am I just doing it wrong?
并非不可想象。不是我的推荐(参见 Boost Spirit: "Semantic actions are evil"?)。但是,是的,你做错了:
如果您不希望它成为公开属性的一部分,您需要 lit("$")
而不是 char_("$")
。其实'$'
这里就可以了
Is there a way to bind a semantic action and still get the output? Like
char_[doSomething] // Can this both call doSomething, and parse a char?
是的。您现在正在这样做,并且它之所以有效,是因为您使用了 operator%=
而不是 operator=
(请参阅文档:http://www.boost.org/doc/libs/1_61_0/libs/spirit/doc/html/spirit/qi/reference/nonterminal/rule.html#spirit.qi.reference.nonterminal.rule.expression_semantics)。
但是,您似乎真的在尝试使用相同的输入两次(原始为 fromFile
和 "cooked" 为 name
?)适得其反,因为自动规则属性propagation also 用你想要的值覆盖 name
fromFile
.
这里唯一快速的出路是只使用 SA。不过,我建议让 VariableHolder
的构造函数负责细节。
Side note: it looks a bit as if the optional parentheses suggest an expression grammar. If so, make that explicit in the grammar, instead of hardcoding a special case in the rule for a
variableName
. If not, carry on :)
这是一个尝试修复:
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
namespace qi = boost::spirit::qi;
namespace phoenix = boost::phoenix;
struct VariableHolder {
std::string name; // contains "varName"
std::string fromFile; // contains "$(varName)" or "$varName"
};
template <typename It, typename Skipper = qi::ascii::space_type> struct P : qi::grammar<It, VariableHolder(), Skipper> {
P() : P::base_type(start) {
auto _name = phoenix::bind(&VariableHolder::name, qi::_val);
auto _fromFile = phoenix::bind(&VariableHolder::fromFile, qi::_val);
variableName = qi::alpha >> +qi::alnum;
variable = '$' >> (variableName | '(' >> variableName >> ')');
start = qi::as_string [ qi::raw [
variable [ _name = qi::_1 ]]
] [ _fromFile = qi::_1 ];
BOOST_SPIRIT_DEBUG_NODES((start)(variable)(variableName))
}
private:
qi::rule<It, std::string(), Skipper> variable;
qi::rule<It, VariableHolder(), Skipper> start;
// lexemes
qi::rule<It, std::string()> variableName;
};
int main() {
using It = std::string::const_iterator;
P<It> const p;
for (std::string const input : {
"$foo1",
"$(bar2)"
})
{
It f = input.begin(), l = input.end();
VariableHolder data;
bool ok = qi::phrase_parse(f, l, p, qi::ascii::space, data);
if (ok) {
std::cout << "Parse success: " << data.name << " (source: '" << data.fromFile << "')\n";
} else {
std::cout << "Parse failure ('" << input << "')\n";
}
if (f != l) {
std::cout << "Remaining unparsed input: '" << std::string(f, l) << "'\n";
}
}
}
版画
Parse success: foo1 (source: '$foo1')
Parse success: bar2 (source: '$(bar2)')