if loop continue 正在再次执行for循环

Question

if eqp_id:
    for rule in items:
        if rule.eqp_pricelist == True:
            print "id 1"
            print rule.id
            continue
        print "id 2 out"
        print rule.id

#outputs:
#id1
#5
#id 2 out
#4

rule.id = 5怎么可能出现在rule.id = 4

之前

此代码用于 product_pricelist 方法 :

def _price_rule_get_multi(self, cr, uid, pricelist, products_by_qty_by_partner, context=None):

Answer 1

正如您在评论中指出的那样，如果使用 items = self.pool.get('product.pricelist.item').browse(cr, uid, item_ids, context=context) 获取 items，则 items 是 Odoo ORM 的 "recordset"，因此您可以使用 sorted() Odoo ORM函数(see documentation):

sorted(key=None, reverse=False) Return the recordset self ordered by key.

Parameters:
key -- either a function of one argument that returns a comparison key for each record, or None, in which case records are ordered according the default model's order
reverse -- if True, return the result in reverse order

为了将此函数应用于您的代码，请按如下方式更改它：

if eqp_id:
    for rule in items.sorted(key=lambda r: r.id):  ## sort by id using sort()...
        if rule.eqp_pricelist == True:
            print "id 1"
            print rule.id
            continue
        print "id 2 out"
        print rule.id

编辑：
我看不清楚你的目标，但也检查 filtered() 是否可以帮助你：

if eqp_id:
    for rule in items.sorted(key=lambda r: r.id).filtered(lambda r: r.eqp_pricelist == True):  ## sort by id using sort() AND filtered using eqp_pricelist == True...
        print "[True?] Rule with eqp_pricelist == %s" % rule.eqp_pricelist
        print rule.id

或：

if eqp_id:
    for rule in items.sorted(key=lambda r: r.id).filtered(lambda r: r.eqp_pricelist == Talse):  ## sort by id using sort() AND filtered using eqp_pricelist == False...
        print "[False?] Rule with eqp_pricelist == %s" % rule.eqp_pricelist
        print rule.id

您也可以只申请 filtered() 而没有 sorted()。

看看这个：for rule in items.filtered("eqp_pricelist"):

if loop continue 正在再次执行for循环

If loop continue is executing for loop again

python

openerp

odoo-9