TypeError: getState is not a function when adding middleware to Redux

TypeError: getState is not a function when adding middleware to Redux

在我的 configureStore.dev.js 文件中使用此代码,在添加 applyMiddleware(reduxImmutableStateInvariant) 时我得到一个 Uncaught TypeError: getState is not a function。当我删除这个添加的中间件时,我的项目运行正常。添加此中间件的正确方法是什么?这是完整的文件:

import {createStore, compose, applyMiddleware} from 'redux';
import rootReducer from '../reducers';
import reduxImmutableStateInvariant from 'redux-immutable-state-invariant';

export default function configureStore(initialState) {
  const store = createStore(rootReducer, initialState, compose(
    // Add other middleware on this line...
    applyMiddleware(reduxImmutableStateInvariant),
    window.devToolsExtension ? window.devToolsExtension() : f => f // add support for Redux dev tools
    )
  );

  if (module.hot) {
    // Enable Webpack hot module replacement for reducers
    module.hot.accept('../reducers', () => {
      const nextReducer = require('../reducers').default; // eslint-disable-line global-require
      store.replaceReducer(nextReducer);
    });
  }

  return store;
}

reduxImmutableStateInvariant 是一个函数,你需要在将它传递给 applyMiddleware 之前调用它。

const store = createStore(rootReducer, initialState, compose(
        // Add other middleware on this line...
        applyMiddleware(reduxImmutableStateInvariant()),
        window.devToolsExtension ? window.devToolsExtension() : f => f // add support for Redux dev tools
    )
);

这在文档中的什么位置?

在 github README docs 中,在导入后调用(通过 require)reduxImmutableStateInvariant。请参阅下面的第三行:

// Be sure to ONLY add this middleware in development!
const middleware = process.env.NODE_ENV !== 'production' ?
  [require('redux-immutable-state-invariant')(), thunk] :
  [thunk];

// Note passing middleware as the last argument to createStore requires redux@>=3.1.0
const store = createStore(
  reducer,
  applyMiddleware(...middleware)
);

为什么 thunk 不是函数?

在thunk中间件中,thunk函数是called before it is returned.

const thunk = createThunkMiddleware();
thunk.withExtraArgument = createThunkMiddleware;

export default thunk;

那么为什么 redux-immutable-state-invariant 是一个函数?

根据代码,您似乎可以传入一个函数 (isImmutable),该函数用于确定 redux 状态中的哪些属性是不可变的。我认为提供您自己的 isImmutable 函数可以让这个中间件与其他不可变库很好地协同工作。

export default function immutableStateInvariantMiddleware(isImmutable = isImmutableDefault) {

这里用的就是那个方法 https://github.com/leoasis/redux-immutable-state-invariant/blob/5ed542246e32b7eec06879b25e5a0a478daf4892/src/trackForMutations.js#L5