MS Unity 中的重复对象名称(应用程序块)

Duplicate object names in MS Unity (App Block)

我会尽量简化!

Unity注册篇:

// ====================================================================
// NOTE:  This fails as the WithName.TypeName is Payload for all jobs!  
// HOW can we make the name for payloads "[JobName].Payload"??
// ====================================================================
_container.RegisterTypes(AllClasses.FromAssembliesInBasePath()
    .Where(type => (typeof(IJob).IsAssignableFrom(type) || typeof(IJobPayload).IsAssignableFrom(type)) && type.IsClass),
    WithMappings.FromAllInterfaces,
    WithName.TypeName,
    WithLifetime.Transient);

其中:

public interface IJob
{
    bool Execute<T>(T payload) where T : class, IJobPayload;
}
public interface IJobPayload
{
    string JobName { get; set; }
    string JobQueueName { get; set; }
    int Id { get; set; }
    JobType JobType { get; set; }
    CronExpression Cron { get; set; }
}

现在我们可以创建各种工作了。类似于:

public class Job1 : IJob
{
    bool IJob.Execute<T>(T payload)
    {
        if (typeof(T) != typeof(Payload))
            throw new ArgumentException($"Expecting an object with a type of {typeof(Payload)}!");

        Console.WriteLine("public class Job1 : IJob");
        return false;
    }

    public class Payload : IJobPayload
    {
        public string JobName { get; set; }
        public string JobQueueName { get; set; }
        public int Id { get; set; }
        public JobType JobType { get; set; }
        public CronExpression Cron { get; set; }
        // --- job specific data -------------------
        public string Job1ExtraData { get; set }
        public datetime Job1Created { get; set }
    }
}

public class Job2 : IJob
{
    bool IJob.Execute<T>(T payload)
    {
        if (typeof(T) != typeof(Payload))
            throw new ArgumentException($"Expecting an object with a type of {typeof(Payload)}!");

        Console.WriteLine("public class Job2 : IJob");
        return false;
    }

    public class Payload : IJobPayload
    {
        public string JobName { get; set; }
        public string JobQueueName { get; set; }
        public int Id { get; set; }
        public JobType JobType { get; set; }
        public CronExpression Cron { get; set; }
        // --- job specific data -------------------
        public string Title { get; set }
        public int Count { get; set }
    }
}

当试图解决 Job1.PayloadJob2.Payload 的具体 class 时,问题就来了。两者在 Unity 中的名称相同:Payload!

由于我正在处理的项目有很多很多工作,我们想要构建一个模板来创建新工作(添加 > 工作),我们更喜欢将有效负载模型作为工作的子项。

现在我有控制器代码接受 Payload 对象的 JSON 表示:

[HttpPost]
public void Post(dynamic json)
{
    var container = UnityHelpers.GetConfiguredContainer();
    var jobName = GetJobNameFromJson(json); // JsonConverter will not work until I can resolve *which* payload definition I want, brute force it for now...
    var job = container.Resolve<IJob>(jobName);
    // ====================================================================
    // how do I get it to a point where this will resolve.
    // (see original NOTE at top of question)
    // ====================================================================
    var payload = container.Resolve(typeof(IJobPayload), $"{jobName}.Payload");

    job.Execute(payload);
}

如何在 Unity(或任何其他 IoC 容器)中使用它?

您正在使用的 RegisterTypes 重载的第三个参数是 Func<Type,string> 类型。 RegisterTypes 方法将为它找到的每个类型调用此委托以获得注册名称。

WithName.TypeName 只是一个静态方法,returns 类型的名称。

您可以创建自己的方法或 lambda 表达式,它们足够智能以检测类型是否为嵌套类型。这是一个例子:

t => t.IsNested ? t.DeclaringType.Name + "." + t.Name : t.Name

因此您的注册声明将如下所示:

_container.RegisterTypes(
    AllClasses.FromAssembliesInBasePath()
        .Where(type => (typeof(IJob).IsAssignableFrom(type) || typeof(IJobPayload).IsAssignableFrom(type)) && type.IsClass),
    WithMappings.FromAllInterfaces,
    t => t.IsNested ? t.DeclaringType.Name + "." + t.Name : t.Name,
    WithLifetime.Transient);