使形状节点的名称与父级相同

Question

如何使形状节点的名称与其父节点的名称相似？（假设每个 geometry/object 只有 1 个形状节点）

例如。 parent_geo 被称为 test_geo1，但是它的形状节点是 testing_geo2Shape 而不是 test_geo1Shape

我尝试执行以下操作：

all = cmds.ls(sl=True, dag=True, shapes=True)
for shape in all:
    prt = cmds.listRelatives(shape, parent=True)
    for i in prt:
        child = cmds.listRelatives(i, c = True)
        for c in child:
            cmds.rename(c, str(prt) + "Shape")

我得到了一些时髦的名字，例如 u_test_geo1__Shape 等

Answer 1

all = cmds.ls(sl=True, dag=True, shapes=True)
for shape in all:
    ''' 
       shape contain the dag path
       exm.:
       grp_a
           grp_aShape
           grp_b
               grp_bShape
       print cmds.ls('grp_a', dag=1, shapes=1)
       >>('grp_a|grp_aShape', 'grp_b|grp_bShape')
       now rename the object, we have already the dag path so 
       the input of the rename command is unique, you can also split the dag 
       path by '|'[0] as parent
    '''
    cmds.rename(shape, "{0}Shape".format(cmds.listRelatives(shape, parent=True)[0]))

测试的层次结构如下：

grp_a
     shape grp_a
     grp_b
          same name like shape grp_c
grp_c
     shape grp_c
     grp_d
          same name like shape grp_c
grp_e
     same name like shape grp_c

select 仅顶部组

使形状节点的名称与父级相同

Making the name of shape node to be the same as the parent

python

maya