Expect 脚本是运行只有一个命令并显示错误

Question

脚本：

#!/usr/bin/expect
set username "sv111111"
set password "Sandy789"
set f [open "servers.txt"]
set hosts [split [read $f] "\n"]
close $f
foreach host $hosts {
#spawn ssh -o StrictHostKeyChecking=no $username@$hosts
spawn ssh $username@$host
expect "$username@$host's password:"
send -- "$password\n"
expect "$"
send -- "sudo -u sandy /opt/sandy/ship/common/tools/arpq.sh\n"
expect "$username@$host's password:"
send -- "$password\n"
expect "$"
send -- "sudo -u sandy /opt/sandy/ship/common/tools/showps2.pl\n"

expect "$"
send -- "exit\n"
expect eof
close
}

在上面的脚本中，它完美地为 servers.txt 文件中提到的所有服务器运行了第一个 sudo 命令。第二个 sudo 命令未执行并显示以下错误。

spawn ssh sv111111@
ssh: : Name or service not known
send: spawn id exp10 not open
    while executing
"send -- "$password\n""
    ("foreach" body line 5)
    invoked from within
"foreach host $hosts {
#spawn ssh -o StrictHostKeyChecking=no $username@$hosts
spawn ssh $username@$host
expect "$username@$host's password:"
send -- ..."
    (file "./sandy_try.sh" line 8)

请帮忙

Answer 1

read 命令抓取文件内容 并带有尾随换行符 。然后，当您按换行符拆分时，列表有一个尾随元素，它是一个空字符串。使用其中之一：

set f [open "servers.txt"]
set hosts [split [read -nonewline $f] "\n"]
# .....................^^^^^^^^^^
close $f
foreach host $hosts { ...

或

set f [open "servers.txt"]
while {[gets $f host] != -1} {
    spawn ssh ...
}
close $f

Expect 脚本是运行只有一个命令并显示错误

Expect script is running only one command and displays an error

unix

expect

Expect 脚本是 运行 只有一个命令并显示错误

Expect script is running only one command and displays an error

unix

expect

Expect 脚本是运行只有一个命令并显示错误