使用 XPath 查询 oracle 数据库时，如何 return 值列表而不是字符串？

Question

我正在使用 XPath 查询 oracle 数据库，其中我查询的字段如下所示：

<!-- language: lang-xml -->
<film>
    <title>Godfather, The</title>
    <year>1972</year>
    <directors>
        <director>Francis Ford Coppola</director>
    </directors>
    <genres>
        <genre>Crime</genre>
        <genre>Drama</genre>
    </genres>
    <plot>Son of a mafia boss takes over when his father is critically wounded in a mob hit.</plot>
    <cast>
        <performer>
            <actor>Marlon Brando</actor>
            <role>Don Vito Corleone</role>
        </performer>
        <performer>
            <actor>Al Pacino</actor>
            <role>Michael Corleone</role>
        </performer>
        <performer>
            <actor>Diane Keaton</actor>
            <role>Kay Adams Corleone</role>
        </performer>
        <performer>
            <actor>Robert Duvall</actor>
            <role>Tom Hagen</role>
        </performer>
        <performer>
            <actor>James Caan</actor>
            <role>Sonny Corleone</role>
        </performer>
    </cast>
</film>

我想return所有出演过《教父》的演员。目前我的代码如下所示：

result = stmt.executeQuery("SELECT a.FILM.extract('/film[title=\"Godfather, The\"]/cast/performer/actor/text()') "
                + "FROM ASS2_Film a "
                + "WHERE a.film.existsNode('/film[title=\"Godfather, The\"]')=1");

System.out.println("\nActor");            

while (result.next()) {   
    System.out.println(result.getString(1)+"\n");
}

此刻我的代码是 returning:

Actor
Marlon BrandoAl PacinoDiane KeatonRobert DuvallJames Caan

如我所愿 return编辑为：

Actor
Marlon Brando
Al Pacino
Diane Keaton
Robert Duvall
James Caan

感谢您的帮助

Answer 1

EXTRACT（和 EXTRACTVALUE）是已弃用的函数。您应该改用 XMLTABLE：

with sample_data as (select xmltype('<film>
    <title>Godfather, The</title>
    <year>1972</year>
    <directors>
        <director>Francis Ford Coppola</director>
    </directors>
    <genres>
        <genre>Crime</genre>
        <genre>Drama</genre>
    </genres>
    <plot>Son of a mafia boss takes over when his father is critically wounded in a mob hit.</plot>
    <cast>
        <performer>
            <actor>Marlon Brando</actor>
            <role>Don Vito Corleone</role>
        </performer>
        <performer>
            <actor>Al Pacino</actor>
            <role>Michael Corleone</role>
        </performer>
        <performer>
            <actor>Diane Keaton</actor>
            <role>Kay Adams Corleone</role>
        </performer>
        <performer>
            <actor>Robert Duvall</actor>
            <role>Tom Hagen</role>
        </performer>
        <performer>
            <actor>James Caan</actor>
            <role>Sonny Corleone</role>
        </performer>
    </cast>
</film>') x from dual)
select x.*
from   sample_data sd,
       xmltable('/film[title="Godfather, The"]/cast/performer' passing sd.x
                columns actor varchar2(50) path '//actor',
                        role varchar2(50) path '//role') x;

ACTOR                                              ROLE                                              
-------------------------------------------------- --------------------------------------------------
Marlon Brando                                      Don Vito Corleone                                 
Al Pacino                                          Michael Corleone                                  
Diane Keaton                                       Kay Adams Corleone                                
Robert Duvall                                      Tom Hagen                                         
James Caan                                         Sonny Corleone

（我包含角色列只是为了提供更多信息；如果不需要，您只需从 XMLTABLE 部分的列列表中删除该列即可。）

使用 XPath 查询 oracle 数据库时，如何 return 值列表而不是字符串？

How do I return a list of values instead of a string when querying a oracle database using XPath?

java

xml

sql

oracle

xpath