如何启用/禁用 jquery 中的按钮?
How to enable /disable buttons in jquery?
我的代码看起来像,
$("#OperationTypeId").change(function () {
var DropdownSelectionValue = $("#OperationTypeId :selected").val();
alert(DropdownSelectionValue );
if (DropdownSelectionValue == 3)
{
$("#Button1Id").attr('disabled');
$(" Button2Id").attr('enable');;
//$("#Button1Id").hide();
}
else {
$("#Button1Id").attr('enable');
$(" Button2Id").attr('disabled');;
}
});
我的代码正确显示警报值,但没有使按钮 enable/disable 具有 DropdownSelectionValue 条件。作为初学者,我不知道该怎么做。请告诉我。
试试这个:-
$("#OperationTypeId").change(function () {
var DropdownSelectionValue = $("#OperationTypeId :selected").val();
if (DropdownSelectionValue == 3) {
$("#Button1Id").attr('disabled','disabled'); //or $("#Button1Id").prop('disabled',true);
$("#Button2Id").removeAttr('disabled'); //Use '#' id selector
}
else {
$("#Button1Id").removeAttr('disabled'); // or $("#Button1Id").prop('disabled',false);
$("#Button2Id").attr('disabled','disabled'); //Use '#' id selector
}
});
您可以使用 jquery prop
相同
$('#Button1Id').prop('disabled', true);
$('#Button2Id').prop('disabled', false);
禁用
$('#Button1Id').attr('disabled','disabled');
启用
$('#Button1Id').removeAttr('disabled');
来自 jQuery 站点
Properties generally affect the dynamic state of a DOM element without changing the serialized HTML attribute.
Examples include the value property of input elements, the disabled property of inputs and buttons, or the checked property of a checkbox.
The .prop() method should be used to set disabled and checked instead of the .attr() method.
禁用:
$('#Button1Id').prop('disabled', true);
启用:
$('#Button2Id').prop('disabled', false);
我的代码看起来像,
$("#OperationTypeId").change(function () {
var DropdownSelectionValue = $("#OperationTypeId :selected").val();
alert(DropdownSelectionValue );
if (DropdownSelectionValue == 3)
{
$("#Button1Id").attr('disabled');
$(" Button2Id").attr('enable');;
//$("#Button1Id").hide();
}
else {
$("#Button1Id").attr('enable');
$(" Button2Id").attr('disabled');;
}
});
我的代码正确显示警报值,但没有使按钮 enable/disable 具有 DropdownSelectionValue 条件。作为初学者,我不知道该怎么做。请告诉我。
试试这个:-
$("#OperationTypeId").change(function () {
var DropdownSelectionValue = $("#OperationTypeId :selected").val();
if (DropdownSelectionValue == 3) {
$("#Button1Id").attr('disabled','disabled'); //or $("#Button1Id").prop('disabled',true);
$("#Button2Id").removeAttr('disabled'); //Use '#' id selector
}
else {
$("#Button1Id").removeAttr('disabled'); // or $("#Button1Id").prop('disabled',false);
$("#Button2Id").attr('disabled','disabled'); //Use '#' id selector
}
});
您可以使用 jquery prop
相同
$('#Button1Id').prop('disabled', true);
$('#Button2Id').prop('disabled', false);
禁用
$('#Button1Id').attr('disabled','disabled');
启用
$('#Button1Id').removeAttr('disabled');
来自 jQuery 站点
Properties generally affect the dynamic state of a DOM element without changing the serialized HTML attribute.
Examples include the value property of input elements, the disabled property of inputs and buttons, or the checked property of a checkbox.
The .prop() method should be used to set disabled and checked instead of the .attr() method.
禁用:
$('#Button1Id').prop('disabled', true);
启用:
$('#Button2Id').prop('disabled', false);