如何在 ios 中按升序对日期数组进行排序

Question

我有一个包含字符串格式日期的 NSMutableArray。在这里，我需要按照日期的升序对该数组进行排序。我使用了 strong text

 NSSortDescriptor *descriptor=[[NSSortDescriptor alloc] initWithKey:@"self" ascending:YES];
 NSArray *descriptors=[NSArray arrayWithObject: descriptor];
 NSArray *reverseOrder=[dateArray sortedArrayUsingDescriptors:descriptors];

但它只按照日和月的升序对日期进行排序。不考虑年份。请帮我。例如，Array 包含

 03/09/2017, 03/06/2016, 01/06/2016,01/04/2016 and 03/01/2017.

使用上面的代码行后，Array contains like,

 01/04/2018, 01/06/2016, 03/01/2017, 03/06/2016, 03/09/2016

Answer 1

您需要像这样使用sortedArrayUsingComparator来使用字符串数组对日期进行排序。

NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:@"MM/dd/yyyy"];
NSArray *sortedArray = [yourArray sortedArrayUsingComparator:^NSComparisonResult(NSString *obj1, NSString *obj2) {
    NSDate *d1 = [df dateFromString: obj1];
    NSDate *d2 = [df dateFromString: obj2];
    return [d1 compare: d2];
}];

注意：设置日期格式根据你的日期，很难从你的例子中预测日期格式，这就是我使用MM/dd/yyyy的原因，如果你的日期包含甲酸盐 dd/MM/yyyy 然后使用它。

Answer 2

您的代码正确，但日期格式错误。

试试这个代码：

NSMutableArray *dateArray = [[NSMutableArray alloc] initWithArray: @[@"03/09/2017", @"03/06/2016", @"01/06/2016",@"01/04/2016", @"03/01/2017"]];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
NSDate *date;
for (int i = 0; i < dateArray.count; i++) {
    [formatter setDateFormat:@"MM/dd/yyyy"];  // Please your date format set.
    date = [formatter dateFromString:[dateArray objectAtIndex:i]];
    [formatter setDateFormat:@"yyyy/MM/dd"];
    [dateArray replaceObjectAtIndex:i withObject:[formatter stringFromDate:date]];
}
NSSortDescriptor *descriptor=[[NSSortDescriptor alloc] initWithKey:@"self" ascending:YES];
NSArray *descriptors=[NSArray arrayWithObject: descriptor];
NSArray *reverseOrder=[dateArray sortedArrayUsingDescriptors:descriptors];

NSLog(@"Array: %@",reverseOrder);

Answer 3

请尝试以下代码：

NSArray *strDateArray = [[NSArray alloc] initWithObjects:@"03/09/2017",@"03/06/2016", @"01/06/2016",@"01/04/2016",@"03/01/2017", nil];

    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    [formatter setDateFormat:@"MM/dd/yyyy"];

    NSMutableArray *dateArray = [[NSMutableArray alloc] init];

    for (NSString *dateString in strDateArray) {
        NSDate *date = [formatter dateFromString:dateString];
        [dateArray addObject:date];
    }

    // sort array of dates
    [dateArray sortUsingComparator:^NSComparisonResult(NSDate *date1, NSDate *date2) {
        // return date1 compare date2 for ascending. And reverse the call for ascending.
        return [date1 compare:date2];
    }];

    NSLog(@"dateArray %@", dateArray);
    NSMutableArray *sortedDateArray = [[NSMutableArray alloc] init];

    for (NSDate *date in dateArray) {
        NSString *dateString = [formatter stringFromDate:date];
        [sortedDateArray addObject:dateString];
    }

    NSLog(@"sortedDateArray %@", sortedDateArray);

Answer 4

对于Swift 4.0

let formater = DateFormatter()
    formater.dateFormat = "MM/dd/yyyy" //date formate should be according to your date formate
    let sortedArray=arrayToSort.sorted(){
        (obj1, obj2) in
        let date1=formater.date(from: obj1)
        let date2=formater.date(from: obj2)
        return date1!<date2!
    }

Answer 5

//你可以根据你的代码更改日期格式

NSDateFormatter *df = [[NSDateFormatter alloc] init];
                      [df setDateFormat:@"MM/dd/yyyy"];

NSArray *sortedArray = [YourArraysortedArrayUsingComparator:^NSComparisonResult(NSDictionary *obj1, NSDictionary *obj2)
{
    NSString *strDateObj1  = [NSString stringWithFormat:@"%@",[obj1 valueForKey:@"BirthDate"]];
    NSString *strDateObj2  = [NSString stringWithFormat:@"%@",[obj2 valueForKey:@"BirthDate"]];
    NSDate *d1 = [df dateFromString: strDateObj1];
    NSDate *d2 = [df dateFromString: strDateObj2];
    return [d1 compare: d2];
}];

NSLog(@"%@", sortedArray)

如何在 ios 中按升序对日期数组进行排序

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