Inputstream没有那个文件目录-Android

Question

我从 Android 的内部存储中选择一个文本文件，例如 Sample.txt 使用 convertFileToByteArray( Uri documentUri)[= 将文件转换为字节数组14=]

Context applicationContext = MainActivity.getContextOfApplication();
private byte[] convertFileToByteArray(Context context, Uri documentUri) {
    ByteArrayOutputStream buffer = null;
    try {
        InputStream inputStream = applicationContext.getContentResolver().openInputStream(documentUri);
        int nRead;
        byte[] data = new byte[16384];
        buffer = new ByteArrayOutputStream();
        while ((nRead = inputStream.read(data, 0, data.length)) != -1) {
            buffer.write(data, 0, nRead);
        }
        buffer.flush();
    } catch (Exception e) {
        e.getLocalizedMessage();
    }
    return buffer.toByteArray();

}

在这一行

InputStream inputStream = applicationContext.getContentResolver().openInputStream(documentUri);

然而，没有捕捉到异常错误，当我选择一个无法识别其扩展名类型的文件时，它会捕捉到异常和 return "No such directory"，例如 Sample.lev1，Sample.abc, Sample.rty

这个android应用程序是加密和解密的，所以我的加密文件扩展名很奇怪，比如.lev1, .abc, .rty。

加密很好，因为我选择了一个可读的文件（.txt、.pdf）但解密不行，因为当尝试将文件（.lev1、.abc、.rty）转换为字节数组时，它会抛出 "FileNotFoundException",

case R.id.btnGO://WILL CRYPT file
                Uri doctUri = chosenFile;
                keyType = MainActivity.keyType;
                if (keyType == null || doctUri == null || radioGroup.getCheckedRadioButtonId() == -1) {
                    setMessage("Selection not Complete !");
                } else {
                    mimeType = getMimeType(getContext(), doctUri);//check file whether it suitable or not.
                    // and to be used for save file
                    if (functionCode == ENCRYPT_FILE) {
                        try {
                            if (mimeType == null || isBCDMimeType(getFileName(doctUri))) {
                                if (isBCDMimeType(getFileName(doctUri))) {

                                    //
                                } else {


                                }
                            } else {
                                byte[] b = convertFileToByteArray(doctUri);
                                launchRingDialogForEF(null, b, mimeType, keyType);
                            }
                        } catch (Exception e) {
                            e.getLocalizedMessage();
                        }
                    } else if (functionCode == DECRYPT_FILE) {
                        if (isVendorMimeType(getFileName(doctUri))) {

                            try {


                                 byte[] b = convertFileToByteArray(doctUri);
                                size = b.length;

                                encryptDecryptHex ead = new encryptDecryptHex();

                                ead.decrypt(usbDeviceConnection, epOUT, epIN, b);

                                returnEData = ead.deData;
                                output = ead.decryptedData;
                                showMessageAfterTryToCrypt(returnEData, output, "Decrypt File", ead.m, ead.k);//m= mimeType k=keyType
                                goOk(usbDeviceConnection, epOUT, epIN);
                            } catch (Exception e) {
                                e.getLocalizedMessage();
                            }
                        } else {

                        }
                    }
                }

Answer 1

如果 os 版本为 6.0 及更高版本，您在访问任何设备存储之前已在运行时获得权限。查看以下官方文档以获取更多信息 https://developer.android.com/training/permissions/requesting.html

Answer 2

Encrypted.ab（例如）的 uri 附加了 "%00"

content://com.android.externalstorage.documents/document/primary%3AEncrypted.a%00b%00%00%00%00%00

Inputstream没有那个文件目录-Android

Inputstream no such file directory-Android

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