检查SQL中的table是否连续出现两个不同的值？

Question

有一个table看起来像这样（有更多的列，但与查询无关）：

DocumentId | DocumentStateId | TransitionMoment
111222       -2                2016-04-21
111222       -1                2016-04-22
111222       -7                2016-04-23
111222       -5                2016-04-24
111222       -6                2016-04-25
111222       -1                2016-04-26
333141       -2                2016-05-01
333141       -7                2016-05-09
333141       -6                2016-05-10
333141       -3                2016-05-15
777525       -1                2016-02-10
777525       -6                2016-02-10
777525       -7                2016-02-10
777525       -5                2016-02-10
777525       -2                2016-02-10

我有哪些选项可以检查文档是否连续从状态“-7”变为状态“-6”（中间没有通过其他状态转换）？在示例文档中。 33141.

提前致谢！

Answer 1

在 SQL Server 2012+ 中，您只需使用 lag()。在 SQL Server 2005 中，您可以使用 apply:

select t.*
from t cross apply
     (select top 1 t2.*
      from t t2
      where t2.documentid = t.documentid and
            t2.transitionmoment > t.transitionmoment
      order by t2.transitionmoment desc
     ) tnext
where t.DocumentStateId = -7 and
      tnext.DocumentStateId = -6;

Answer 2

使用 LEAD():

WITH CTE AS
(
SELECT 
DocumentId, DocumentStateId, TransitionMoment,
LEAD(DocumentStateId) OVER (ORDER BY TransitionMoment) NextSIDVal,
LEAD(DocumentId) OVER (ORDER BY DocumentId) NextDIDVal
FROM Table
)

SELECT DocumentId, DocumentStateId, TransitionMoment FROM CTE
WHERE DocumentStateId = -7 AND NextSIDVal = -6
AND DocumentId = NextDIDVal

使用ROW_NUMBER():

WITH CTE AS
(
SELECT 
DocumentId, DocumentStateId, TransitionMoment, ROW_NUMBER() OVER (ORDER BY TransitionMoment) RowVal
FROM Table
)

SELECT x.DocumentId, x.DocumentStateId, x.TransitionMoment
FROM CTE x
JOIN CTE y
ON x.RowVal + 1 = y.RowVal
WHERE x.DocumentStateId = -7 AND y.DocumentStateId = -6
AND x.DocumentId = y.DocumentId

检查SQL中的table是否连续出现两个不同的值？

Check if two different values appear successively in a table in SQL?

sql

sql-server

sql-server-2005