如何使用从 SQL 查询生成的按钮获得 id/name onclick?

How would I get an id/name onclick using buttons generated from an SQL query?

我正在从 MySQL 数据库创建 table。目前,我可以手动输入Course ID,然后点击'select',根据输入的Course ID显示花名册。

不过,我想在每一行之后的 table 右侧使用按钮来简化此操作。做这个的最好方式是什么?我可以提供截图,但我仍然需要更多的声誉。

所以生成这个table的代码如下。

<?php
// Connection information to database has been removed. 

// $Row[1] - first name of faculty
// $Row[2] - last name of faculty
// $fieldRow[0] - course ID
// $fieldRow[1] - course name
// $fieldRow[2] - course year
// $fieldRow[3] - number of units

echo "<table>
<caption>....for " . $Row[1] . " " . $Row[2] . "</caption>
<tr>
  <th>Course ID</th>
  <th>Course Name</th>
  <th>Course Year</th>
  <th>Units</th>
</tr>";
while ($fieldRow = mysqli_fetch_row($result2))
{
    echo "<tr><td>" . $fieldRow[0] . "</td>
    <td>" . $fieldRow[1] . "</td>
    <td>" . $fieldRow[2] . "</td>
    <td>" . $fieldRow[3] . "</td>
    <td><button name='" . $fieldRow[0] . "'>Select</button></td>
    </tr>";
}
echo "</table>";
?>

<form method="get" action="class.php">
  <p>Enter Course ID
    <input autofocus="autofocus" tabindex="1" type="text" maxlength="5" name="classSelect" title="Enter Class Number" />
  </p>
  <p>
    <button tabindex="2" type="submit">Select</button>
  </p>
</form>

感谢您的关注!

你可以有类似

if(isset($_GET['id'])
{
  $course_id = intval($_GET['id']);
  // Do your query against the course id.
}

 while ($fieldRow = mysqli_fetch_row($result2))
    {
      echo "<tr><td>" . $fieldRow[0] . "</td>
      <td>" . $fieldRow[1] . "</td>
      <td>" . $fieldRow[2] . "</td>
      <td>" . $fieldRow[3] . "</td>
      <td><a href='" . ?id=$fieldRow[0] . "'>Select</a></td>
      </tr>";
    }
    echo "</table>";
    ?>

您可以使用 JQuery 来做到这一点

在您的代码中

echo "<tr><td>" . $fieldRow[0] . "</td>
<td>" . $fieldRow[1] . "</td>
<td>" . $fieldRow[2] . "</td>
<td>" . $fieldRow[3] . "</td>
<td><button name='" . $fieldRow[0] . "' class='selecter'>Select</button></td>
</tr>";

然后像这样添加头像

<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
    $(".selecter").click(function(){
        $("input").val($(this).attr("name"));
    });
});
</script>
</head>

完整代码

<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
    $(".selecter").click(function(){
        $("input").val($(this).attr("name"));
    });
});
</script>
</head>
<body>
 <?php
    // Connection information to database has been removed. 

    // $Row[1] - first name of faculty
    // $Row[2] - last name of faculty
    // $fieldRow[0] - course ID
    // $fieldRow[1] - course name
    // $fieldRow[2] - course year
    // $fieldRow[3] - number of units

 echo "<table>
<caption>....for " . $Row[1] . " " . $Row[2] . "
</caption>
    <tr>
<th>Course ID</th>
<th>Course Name</th>
<th>Course Year</th>
<th>Units</th>
</tr>";
    while ($fieldRow = mysqli_fetch_row($result2))
    {
      echo "<tr><td>" . $fieldRow[0] . "</td>
<td>" . $fieldRow[1] . "</td>
<td>" . $fieldRow[2] . "</td>
<td>" . $fieldRow[3] . "</td>
<td><button name='" . $fieldRow[0] . "' class='selecter'>Select</button></td>
</tr>";
    }
    echo "</table>";
    ?>

    <form method="get" action="class.php">
    <p>Enter Course ID
      <input autofocus="autofocus" tabindex="1" type="text" maxlength="5" name="classSelect" title="Enter Class Number" />
    </p>
    <p>
      <button tabindex="2" type="submit">Select</button>
    </p>
    </form>
</body>
</html>