SWIFT 3 NSArray 的谓词无法正确处理数字
SWIFT 3 Predicate for NSArray not working properly with numbers
我正在学习使用谓词进行过滤。我找到了一个教程,但是在 Swift 3 中有一个方面对我不起作用。这是一些具体的代码:
let ageIs33Predicate01 = NSPredicate(format: "age = 33") //THIS WORKS
let ageIs33Predicate02 = NSPredicate(format: "%K = 33", "age") //THIS WORKS
let ageIs33Predicate03 = NSPredicate(format: "%K = %@", "age","33") //THIS DOESN'T WORK
let ageIs33Predicate04 = NSPredicate(format: "age = %@","33") //THIS DOESN'T WORK
全部 4 个编译,但最后两个没有结果,即使我有一个 age = 33 的情况。这是教程中的测试完整测试代码:
import Foundation
class Person: NSObject {
let firstName: String
let lastName: String
let age: Int
init(firstName: String, lastName: String, age: Int) {
self.firstName = firstName
self.lastName = lastName
self.age = age
}
override var description: String {
return "\(firstName) \(lastName)"
}
}
let alice = Person(firstName: "Alice", lastName: "Smith", age: 24)
let bob = Person(firstName: "Bob", lastName: "Jones", age: 27)
let charlie = Person(firstName: "Charlie", lastName: "Smith", age: 33)
let quentin = Person(firstName: "Quentin", lastName: "Alberts", age: 31)
let people = [alice, bob, charlie, quentin]
let ageIs33Predicate01 = NSPredicate(format: "age = 33")
let ageIs33Predicate02 = NSPredicate(format: "%K = 33", "age")
let ageIs33Predicate03 = NSPredicate(format: "%K = %@", "age","33")
let ageIs33Predicate04 = NSPredicate(format: "age = %@","33")
(people as NSArray).filtered(using: ageIs33Predicate01)
// ["Charlie Smith"]
(people as NSArray).filtered(using: ageIs33Predicate02)
// ["Charlie Smith"]
(people as NSArray).filtered(using: ageIs33Predicate03)
// []
(people as NSArray).filtered(using: ageIs33Predicate04)
// []
我做错了什么?谢谢
为什么最后两个会起作用?您正在为 Int
属性 传递一个字符串。您需要传入一个 Int
来与 Int
属性.
进行比较
将最后两个改为:
let ageIs33Predicate03 = NSPredicate(format: "%K = %d", "age", 33)
let ageIs33Predicate04 = NSPredicate(format: "age = %d", 33)
请注意格式说明符从 %@
到 %d
的变化。
我正在学习使用谓词进行过滤。我找到了一个教程,但是在 Swift 3 中有一个方面对我不起作用。这是一些具体的代码:
let ageIs33Predicate01 = NSPredicate(format: "age = 33") //THIS WORKS
let ageIs33Predicate02 = NSPredicate(format: "%K = 33", "age") //THIS WORKS
let ageIs33Predicate03 = NSPredicate(format: "%K = %@", "age","33") //THIS DOESN'T WORK
let ageIs33Predicate04 = NSPredicate(format: "age = %@","33") //THIS DOESN'T WORK
全部 4 个编译,但最后两个没有结果,即使我有一个 age = 33 的情况。这是教程中的测试完整测试代码:
import Foundation
class Person: NSObject {
let firstName: String
let lastName: String
let age: Int
init(firstName: String, lastName: String, age: Int) {
self.firstName = firstName
self.lastName = lastName
self.age = age
}
override var description: String {
return "\(firstName) \(lastName)"
}
}
let alice = Person(firstName: "Alice", lastName: "Smith", age: 24)
let bob = Person(firstName: "Bob", lastName: "Jones", age: 27)
let charlie = Person(firstName: "Charlie", lastName: "Smith", age: 33)
let quentin = Person(firstName: "Quentin", lastName: "Alberts", age: 31)
let people = [alice, bob, charlie, quentin]
let ageIs33Predicate01 = NSPredicate(format: "age = 33")
let ageIs33Predicate02 = NSPredicate(format: "%K = 33", "age")
let ageIs33Predicate03 = NSPredicate(format: "%K = %@", "age","33")
let ageIs33Predicate04 = NSPredicate(format: "age = %@","33")
(people as NSArray).filtered(using: ageIs33Predicate01)
// ["Charlie Smith"]
(people as NSArray).filtered(using: ageIs33Predicate02)
// ["Charlie Smith"]
(people as NSArray).filtered(using: ageIs33Predicate03)
// []
(people as NSArray).filtered(using: ageIs33Predicate04)
// []
我做错了什么?谢谢
为什么最后两个会起作用?您正在为 Int
属性 传递一个字符串。您需要传入一个 Int
来与 Int
属性.
将最后两个改为:
let ageIs33Predicate03 = NSPredicate(format: "%K = %d", "age", 33)
let ageIs33Predicate04 = NSPredicate(format: "age = %d", 33)
请注意格式说明符从 %@
到 %d
的变化。