我需要另一双眼睛来告诉我我在哪里又笨了(关于计算)

I need another pair of eye to tell me where I am being dumb again (about calculations)

我实际上是在尝试做一些事情,比如通过知道日期 e.g.February 1950 年 20 日是星期一来计算星期几。当然还有很多其他问题,我已经有了公式。 事情不知何故,当我添加一个 if 语句时,假设我得到 3,我得到 2,如果我应该得到 0,我得到 -1。有人可以帮我看看有什么问题吗?

这些是我需要的输出的月份代码变量,这是输出不断得到比预期错误的输出的部分。

/* Month Code */
private static int JAN_CODE = 1;
private static int FEB_CODE = 4;
private static int MAR_CODE = 4;
private static int APR_CODE = 0;
private static int MAY_CODE = 2;
private static int JUN_CODE = 5;
private static int JUL_CODE = 0;
private static int AUG_CODE = 3;
private static int SEP_CODE = 6;
private static int OCT_CODE = 1;
private static int NOV_CODE = 4;
private static int DEC_CODE = 6;

闰年计算和return判断真假

private boolean isLeapYear(){
    if((year % 100 == 0) && (year % 400 != 0))
    {
        return false;
    }else if(year % 4 == 0)
    {
        return true;
    }else{
        return false;
    }
}

这是 return monthCode 的部分,具体取决于月份的整数

 public int getMonthCode(){
    // variable to store the code
    int monthCode;

    // January and February dates in leap years: subtract 1
    boolean i = isLeapYear();
    if (i == true){
        JAN_CODE -= 1;
        FEB_CODE -= 1;
    }

    // Check which month uses which month code
    switch (month){
        case JANUARY_INT: monthCode = JAN_CODE;
            break;
        case FEBURARY_INT: monthCode = FEB_CODE;
            break;
        case MARCH_INT: monthCode = MAR_CODE;
            break;
        case APRIL_INT: monthCode = APR_CODE;
            break;
        case MAY_INT: monthCode = MAY_CODE;
            break;
        case JUNE_INT: monthCode = JUN_CODE;
            break;
        case JULY_INT: monthCode = JUL_CODE;
            break;
        case AUGUST_INT: monthCode = AUG_CODE;
            break;
        case SEPTEMBER_INT: monthCode = SEP_CODE;
            break;
        case OCTOBER_INT: monthCode = OCT_CODE;
            break;
        case NOVEMBER_INT: monthCode = NOV_CODE;
            break;
        case DECEMBER_INT: monthCode = DEC_CODE;
            break;
        default: monthCode = 0;
    }
    return monthCode;
}

查看内容的简单代码 returned

public void getCode(){
    System.out.println("Code: "+getMonthCode());
}

我尝试使用 JAN_CODE = JAN_CODE - 1; 仍然得到错误的输出。 所以假设如果输入一月,如果不是闰年,我得到的 JAN_CODE 将是 1,但如果是闰年,它应该是 0,但在我输入 if(i == true) 语句后查看如果是闰年并且输入了 1 月,我得到的 monthCode 是 -1,如果是 2 月,我得到 2,但我应该在 1 月得到 0,在 2 月得到 3,不是吗? 如果我取出 if 语句,那么 returned 是 1 月的 1 和 4 月的 2 月

有人可以帮帮我吗?

我将从修改您的函数处理数据、传递参数而不是使用静态内容的方式开始。这应该让您了解如何解决它:

private boolean isLeapYear(inYear){
    if((inYear % 100 == 0) && (inYear % 400 != 0))
    {
        return false;
    }else if(inYear % 4 == 0)
    {
        return true;
    }else{
        return false;
    }
}

private int getNewMonthCode(inYear, inMonthCode) {
    if (isLeapYear(inYear)) {
        return inMonthCode-1;
    }
    return inMonthCode;
}

public int getMonthCode(inYear, inMonth) {
    // variable to store the code
    int monthCode;

    // Check which month uses which month code
    switch (inMonth){
        case JANUARY_INT: monthCode = getNewMonthCode(inYear, JAN_CODE);
            break;
        case FEBURARY_INT: monthCode = getNewMonthCode(inYear, FEB_CODE);
            break;
        case MARCH_INT: monthCode = MAR_CODE;
            break;
        case APRIL_INT: monthCode = APR_CODE;
            break;
        case MAY_INT: monthCode = MAY_CODE;
            break;
        case JUNE_INT: monthCode = JUN_CODE;
            break;
        case JULY_INT: monthCode = JUL_CODE;
            break;
        case AUGUST_INT: monthCode = AUG_CODE;
            break;
        case SEPTEMBER_INT: monthCode = SEP_CODE;
            break;
        case OCTOBER_INT: monthCode = OCT_CODE;
            break;
        case NOVEMBER_INT: monthCode = NOV_CODE;
            break;
        case DECEMBER_INT: monthCode = DEC_CODE;
            break;
        default: monthCode = 0;
    }
    return monthCode;
}

由 System.out.println("Code: " + getMonthCode(1954,1)) 调用; //1954 年 1 月

您仍然可以使用您的 global/static 变量:getMonthCode(year,month)