在单元测试的开关案例中的特定情况下,如何仅调用一个函数?

How to call a function only, when in a specific case in a switch case for unit test?

所以我有一个 class 可以有 4 个状态的门控

public enum DoorControlState
{
    DoorClosed,
    DoorOpening,
    DoorOpen,
    DoorBreached

}

要打开门,需要一个访问代码,然后验证该代码,如果正确则打开门。如果门不处于关闭状态,则不会发生任何事情。它应该像这样 RequestEntry(id)[Doorcontrol]->ValidateEntryRequest(id)[IUserValidation]->OK[Doorcontrol]->Open[IDoor]->将状态更改为 DoorOpening。然后Idoor调用DoorOpen,状态变为DoorOpen等。

我已经实现了 DoorControl class 如下

public class DoorControl
{
    private IDoor _door;
    private IEntryNotification _entryNotification;
    private IUserValidation _userValidation;
    private DoorControlState _doorControlState;
    private int _id;

    public DoorControl(IDoor door, IEntryNotification entryNotification, IUserValidation userValidation, DoorControlState doorControlState)
    {
        _door = door;
        _entryNotification = entryNotification;
        _userValidation = userValidation;
        _doorControlState = doorControlState;
    }

    public void Run()
    {
        switch (_doorControlState)
        {
            case DoorControlState.DoorClosed:

                bool foo = RequestEntryId();
                if (foo)
                {
                    _door.Open();
                    _doorControlState = DoorControlState.DoorOpening;
                }
                break;
            case DoorControlState.DoorOpening:
                _door.Close();
                _doorControlState = DoorControlState.DoorOpen;
                break;
            case DoorControlState.DoorOpen:
                // Do stuff....                  
                break;
            case DoorControlState.DoorBreached:
                // Do stuff
                break;
            default:
                throw new InvalidEnumArgumentException();
            }
    }

    private bool RequestEntryId()
    {
        bool maybeFoo = _userValidation.ValidateEnetryRequest();
        if (maybeFoo = true)
        {
            return true;
        }

        return false;
    }

    public void DoorOpened()
    {
        //
    }

    public void DoorClosed()
    {
        //
    }
}

}

UserValidation 和 Door classes 实现为接口

public interface IUserValidation
{
    bool ValidateEnetryRequest();

}

public interface IDoor
{

    void Open();

    void Close();

}

我正在使用 Nunit 和 NSubstitute 测试我的代码

namespace DoorControl.Unit.Test
{
[TestFixture]
public class DoorControlUnitTest
{
    private DoorControl _uut;
    private IDoor _door;
    private IEntryNotification _entryNotification;
    private IUserValidation _userValidation;
    private DoorControlState _doorControlState;

    [SetUp]

    public void SetUp()
    {
        _door = Substitute.For<IDoor>();
        _entryNotification = Substitute.For<IEntryNotification>();
        _userValidation = Substitute.For<IUserValidation>();
        _doorControlState = DoorControlState.DoorClosed;

    _uut = new DoorControl(_door, _entryNotification, _userValidation, _doorControlState);
    }

    [Test]
    public void InputCorrectId()
    {
        _userValidation.ValidateEnetryRequest().Returns(true);
        _uut.RequestEntryId();  // Can't called that cause it's private

        _door.Received().Open();

    }

}
}

我不知道如何让它只在它处于关门状态时调用 RequestEntryId,而在它处于其他状态时忽略它。

编辑:Doorcontrol 所处的状态应该对其他人隐藏。

public void InputCorrectId()
    {
        _userValidation.ValidateEnetryRequest().Returns(true);
        if(_doorControlState == DoorControlState.DoorClosed){
            _uut.RequestEntryId();  // Make it public
        }
        _door.Received().Open();

    }

或者进门控class喜欢:

 case DoorControlState.DoorClosed:
    RequestEntryId();

我不确定你到底在问什么:你说 "I can't figure out how to make it call RequestEntryId only when it's in the Doorclosed state and ignore it if it's in another state." 是指单元测试吗?我不明白你为什么要那样做。请提供更多信息,如果我能提供帮助,我会更新此答案。

不过,我确实注意到了一些可能对您有所帮助的事情。首先RequestEntryId有问题:

private bool RequestEntryId()
{
    bool maybeFoo = _userValidation.ValidateEnetryRequest();
    if (maybeFoo = true)
    {
        return true;
    }
    return false;
}

这里maybeFoo = true是一个覆盖ValidateEntryRequest()结果的赋值。我认为你打算与 == 进行比较,但整个方法可以简化为:

private bool RequestEntryId()
{
    return _userValidation.ValidateEnetryRequest();
}

有了这个修复,我们可以 运行 一些测试来检查 public Run 方法的行为。鉴于您的 SetUp 创建的门控已经处于 Closed 状态,我们可以测试门是否为有效用户打开,而不为无效用户打开。

    [Test]
    public void ClosedDoorOpensWhenUserIsValid()
    {
        _userValidation.ValidateEnetryRequest().Returns(true);
        _uut.Run();
        _door.Received().Open();
    }

    [Test]
    public void ClosedDoorDoesNotOpenWhenUserInvalid()
    {
        _userValidation.ValidateEnetryRequest().Returns(false);
        _uut.Run();
        _door.DidNotReceive().Open();
    }

我们还可以检查是否对已打开的门重复验证:

    [Test]
    public void OpenDoorDoesNotRevalidate()
    {
        _userValidation.ValidateEnetryRequest().Returns(true);
        _uut.Run();

        _userValidation.ClearReceivedCalls();
        _uut.Run();
        _userValidation.DidNotReceive().ValidateEnetryRequest();
    }

希望这能给您一些测试的想法。