XPath：查询多个属性

Question

我可以使用 XPath 从 XML 节点查询多个属性吗？特别是来自子节点？例如

<outer>
  <inner attr1="value1" attr2="value2">
      <leaf attr3="value3" />
  </inner>
  <inner attr1="value1Inner1" attr2="valueInner12">
      <leaf attr3="value_leaf2" />
  </inner>
</outer>

我想得到类似的东西

[
  ["value1", "value2", "value3"],
  ["value1Inner1", "valueInner12", value_leaf2"]
]

Answer 1

试试这个查询：

//*/@*[starts-with(name(), 'attr')]

此查询匹配具有以 attr.

开头的属性的任何节点

DEMO

Answer 2

是的，属性只是节点。但它无法获取嵌套节点列表。因此，为了获得所需的结果，您首先需要 select inner 个元素。迭代它们并从它们及其后代中获取所有属性。

获取`内部？元素节点：

/outer/inner

以及上下文节点及其后代的属性：

descendant-or-self::*/@*

演示：

$xml = <<<'XML'
<outer>
  <inner attr1="value1" attr2="value2">
      <leaf attr3="value3" />
  </inner>
  <inner attr1="value1Inner1" attr2="valueInner12">
      <leaf attr3="value_leaf2" />
  </inner>
</outer>
XML;

$dom = new DOMDocument();
$dom->loadXml($xml);
$xpath = new DOMXPath($dom);

foreach ($xpath->evaluate('/outer/inner') as $inner) {
  $attributes = array_map(
    function (DOMAttr $node) {
      return $node->value;
    },
    iterator_to_array(
      $xpath->evaluate('descendant-or-self::*/@*', $inner)
    )
  );
  var_dump($attributes);
}

输出：

array(3) {
  [0]=>
  string(6) "value1"
  [1]=>
  string(6) "value2"
  [2]=>
  string(6) "value3"
}
array(3) {
  [0]=>
  string(12) "value1Inner1"
  [1]=>
  string(12) "valueInner12"
  [2]=>
  string(11) "value_leaf2"
}

XPath：查询多个属性

XPath: Query multiple attributes

xml

xpath