Python 中的元类基础是什么?
What are metaclass bases in Python?
我正在尝试扩展 django-allauth 来做一些特定于我的项目的事情。我基本上是在尝试在 django-allauth 之上编写自己的包装器,并希望安装、配置和其他内容与 allauth 非常相似。
为此,我开始从 allauth/accounts/app_settings.py
扩展 AppSettings
class。我创建了自己的 app_settings.py
做了这样的事情:
from allauth.account import app_settings as AllAuthAppSettings
class MyAppSettings (AllAuthAppSettings):
def __init__(self, prefix):
# do something
此外,在 app_settings.py 的末尾,我简单地添加了以下内容(从 django-allauth 本身复制):
import sys
my_app_settings = MyAppSettings('MY_PREFIX_')
my_app_settings.__name__ = __name__
sys.modules[__name__] = my_app_settings
现在,当我开始我的项目时,出现以下错误:
TypeError: Error when calling the metaclass bases
__init__() takes exactly 2 arguments (4 given)
老实说,我对 Python-Django 世界还很陌生,并不真正理解最后四行中发生了什么。
什么是元class碱基?传递给它的四个参数是什么?如何让这个流程发挥作用?
这是堆栈跟踪:
Unhandled exception in thread started by <function wrapper at 0x104146578>
Traceback (most recent call last):
File "/Users/user/anaconda/lib/python2.7/site-packages/django/utils/autoreload.py", line 226, in wrapper
fn(*args, **kwargs)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/core/management/commands/runserver.py", line 109, in inner_run
autoreload.raise_last_exception()
File "/Users/user/anaconda/lib/python2.7/site-packages/django/utils/autoreload.py", line 249, in raise_last_exception
six.reraise(*_exception)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/utils/autoreload.py", line 226, in wrapper
fn(*args, **kwargs)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/__init__.py", line 18, in setup
apps.populate(settings.INSTALLED_APPS)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/apps/registry.py", line 108, in populate
app_config.import_models(all_models)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/apps/config.py", line 202, in import_models
self.models_module = import_module(models_module_name)
File "/Users/user/anaconda/lib/python2.7/importlib/__init__.py", line 37, in import_module
__import__(name)
File "/Users/user/myproject/my_app/models.py", line 18, in <module>
from .model_managers import *
File "/Users/user/myproject/my_app/model_managers.py", line 89, in <module>
from . import app_settings
File "/Users/user/myproject/my_app/app_settings.py", line 9, in <module>
TypeError: Error when calling the metaclass bases
__init__() takes exactly 2 arguments (4 given)
看起来你不应该继承自 AllAuthAppSettings
django-allauth
包正在做一些非常丑陋的 python 魔法
import sys # noqa
app_settings = AppSettings('ACCOUNT_')
app_settings.__name__ = __name__
sys.modules[__name__] = app_settings
基本上,当您导入 app_settings
模块时,它会创建 AppSettings
class 的实例,将其重命名为 app_settings
模块的名称,并且然后 将导入的模块替换为 class!
的实例
您不能从 class 个实例继承。我猜你想继承非实例化 AppSettings
class。为此,您需要继承 app_settings
的 class
,而不是直接 app_settings
from allauth.account import app_settings as AllAuthAppSettings
class MyAppSettings(AllAuthAppSettings.__class__):
...
我认为您不需要从 app_settings
模块末尾复制这些行来将您的模块破解成 class.
我正在尝试扩展 django-allauth 来做一些特定于我的项目的事情。我基本上是在尝试在 django-allauth 之上编写自己的包装器,并希望安装、配置和其他内容与 allauth 非常相似。
为此,我开始从 allauth/accounts/app_settings.py
扩展 AppSettings
class。我创建了自己的 app_settings.py
做了这样的事情:
from allauth.account import app_settings as AllAuthAppSettings
class MyAppSettings (AllAuthAppSettings):
def __init__(self, prefix):
# do something
此外,在 app_settings.py 的末尾,我简单地添加了以下内容(从 django-allauth 本身复制):
import sys
my_app_settings = MyAppSettings('MY_PREFIX_')
my_app_settings.__name__ = __name__
sys.modules[__name__] = my_app_settings
现在,当我开始我的项目时,出现以下错误:
TypeError: Error when calling the metaclass bases
__init__() takes exactly 2 arguments (4 given)
老实说,我对 Python-Django 世界还很陌生,并不真正理解最后四行中发生了什么。
什么是元class碱基?传递给它的四个参数是什么?如何让这个流程发挥作用?
这是堆栈跟踪:
Unhandled exception in thread started by <function wrapper at 0x104146578>
Traceback (most recent call last):
File "/Users/user/anaconda/lib/python2.7/site-packages/django/utils/autoreload.py", line 226, in wrapper
fn(*args, **kwargs)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/core/management/commands/runserver.py", line 109, in inner_run
autoreload.raise_last_exception()
File "/Users/user/anaconda/lib/python2.7/site-packages/django/utils/autoreload.py", line 249, in raise_last_exception
six.reraise(*_exception)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/utils/autoreload.py", line 226, in wrapper
fn(*args, **kwargs)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/__init__.py", line 18, in setup
apps.populate(settings.INSTALLED_APPS)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/apps/registry.py", line 108, in populate
app_config.import_models(all_models)
File "/Users/user/anaconda/lib/python2.7/site-packages/django/apps/config.py", line 202, in import_models
self.models_module = import_module(models_module_name)
File "/Users/user/anaconda/lib/python2.7/importlib/__init__.py", line 37, in import_module
__import__(name)
File "/Users/user/myproject/my_app/models.py", line 18, in <module>
from .model_managers import *
File "/Users/user/myproject/my_app/model_managers.py", line 89, in <module>
from . import app_settings
File "/Users/user/myproject/my_app/app_settings.py", line 9, in <module>
TypeError: Error when calling the metaclass bases
__init__() takes exactly 2 arguments (4 given)
看起来你不应该继承自 AllAuthAppSettings
django-allauth
包正在做一些非常丑陋的 python 魔法
import sys # noqa
app_settings = AppSettings('ACCOUNT_')
app_settings.__name__ = __name__
sys.modules[__name__] = app_settings
基本上,当您导入 app_settings
模块时,它会创建 AppSettings
class 的实例,将其重命名为 app_settings
模块的名称,并且然后 将导入的模块替换为 class!
您不能从 class 个实例继承。我猜你想继承非实例化 AppSettings
class。为此,您需要继承 app_settings
的 class
,而不是直接 app_settings
from allauth.account import app_settings as AllAuthAppSettings
class MyAppSettings(AllAuthAppSettings.__class__):
...
我认为您不需要从 app_settings
模块末尾复制这些行来将您的模块破解成 class.