如何在 php 中显示来自 show table 模式查询的数组
How to show array from show table schema query in php
我有一个问题
$qdrop=mysqli_query($connect,"select TABLE_NAME,create_time
FROM INFORMATION_SCHEMA.TABLES
WHERE table_schema = 'purbalingga'
AND CREATE_TIME <='2016-10-07' and TABLE_NAME LIKE '2016%'");
然后显示数组
while ($datadrop=mysqli_fetch_array($qdrop)) {
echo $qdrop['TABLE_NAME'];echo"<br/>";
}
但是我得到一个错误:
Fatal error: Cannot use object of type mysqli_result as array in E:\xampp\htdocs
替换:
while ($datadrop=mysqli_fetch_array($qdrop)) {
echo $qdrop['TABLE_NAME'];
echo"<br/>";
}
与:
while ($datadrop=mysqli_fetch_array($qdrop)) {
echo $datadrop['TABLE_NAME'];
echo"<br/>";
}
$qdrop
仅包含查询,但 $datadrop
是包含 result in array
.
的查询
我有一个问题
$qdrop=mysqli_query($connect,"select TABLE_NAME,create_time
FROM INFORMATION_SCHEMA.TABLES
WHERE table_schema = 'purbalingga'
AND CREATE_TIME <='2016-10-07' and TABLE_NAME LIKE '2016%'");
然后显示数组
while ($datadrop=mysqli_fetch_array($qdrop)) {
echo $qdrop['TABLE_NAME'];echo"<br/>";
}
但是我得到一个错误:
Fatal error: Cannot use object of type mysqli_result as array in E:\xampp\htdocs
替换:
while ($datadrop=mysqli_fetch_array($qdrop)) {
echo $qdrop['TABLE_NAME'];
echo"<br/>";
}
与:
while ($datadrop=mysqli_fetch_array($qdrop)) {
echo $datadrop['TABLE_NAME'];
echo"<br/>";
}
$qdrop
仅包含查询,但 $datadrop
是包含 result in array
.