Django

Question

（首先抱歉我的英语不好）当用户保存更改时，我正在尝试在 UpdateView 中显示一条消息！

这是我的看法

class NeedUpdateView(UpdateView):
    model = Need
    template_name = 'purchases/needs_update_form.html'
    pk_url_kwarg = 'need_id'
    success_message = 'List successfully saved!!!!'
    fields = [
        'detail',
    ]

当您保存应用程序时会加载相同的模板！但我喜欢在保存对象时显示 bootstrap 警报！

这是模板中用于显示消息的代码

{% if messages %}
<div class="alert alert-success">
    {% for m in messages %}
    <li{% if message.tags %} class="{{ message.tags }}"{% endif %}>{{ m }}</li>
    {% endfor %}
</div>
{% endif %}

我在设置中添加了这个

MESSAGE_STORAGE = 'django.contrib.messages.storage.session.SessionStorage'

但是我无法显示消息！对象中的更改保存完好只需要显示消息！

编辑：我在这里显示我的设置，以表明我遵循了文档中的所有步骤

MIDDLEWARE = [
    'django.middleware.security.SecurityMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.locale.LocaleMiddleware',
    'django.middleware.common.CommonMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.middleware.clickjacking.XFrameOptionsMiddleware',
]

DJANGO_APPS = [
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',
]

TEMPLATES = [
    {
        'BACKEND': 'django.template.backends.django.DjangoTemplates',
        'DIRS': [os.path.join(BASE_DIR, "templates")],
        'APP_DIRS': True,
        'OPTIONS': {
            'context_processors': [
                'django.template.context_processors.debug',
                'django.template.context_processors.request',
                'django.contrib.auth.context_processors.auth',
                'django.contrib.messages.context_processors.messages',
                'django.template.context_processors.i18n',
                'apps.cart.context_processors.cart',
            ],
        },
    },
]

Answer 1

要enable the messages in class based views，您需要使用SuccessMessageMixin。

from django.contrib.messages.views import SuccessMessageMixin

class NeedUpdateView(SuccessMessageMixin, UpdateView):
    ...
    success_message = 'List successfully saved!!!!'

Answer 2

您也可以像这样覆盖 form_valid 方法：

from django.contrib import messages
from django.http import HttpResponseRedirect

class NeedUpdateView(UpdateView):
   ...
   def form_valid(self, form):
      messages.success(self.request, "This is my success message")
      super().form_valid(form)
      return HttpResponseRedirect(self.get_success_url())

Django - 如何使用 UpdateView CBV 发送成功消息

Django - How to send a success message using a UpdateView CBV

django-class-based-views