如何使变量等于 C++ 中的字母？

Question

我尝试用 C++ 编写一个简单的程序，因为我是初学者。该程序应该告诉您 "swag value"，因此如果您在控制台中输入除 "Nicu" 以外的任何内容，这是我一位朋友的名字，该程序将显示 "Swag level over 9000"。如果你写 "Nicu"，虽然它会说 "Sorry, couldn't find swag in the database"。我的问题是如何让程序在我写 "Nicu" 时给我答案？以下是我对程序的看法：

#include<iostream>
#include<cstdlib>
using namespace std;

int main()
{
    char b,a;
    a='Nicu';
    cout<<"Insert your name: ";
    cin>>b;
    if (b==a){
    cout<<"Sorry ! Couldn't find swag in database... "<<endl;
}
    else if (b!=a){
    cout<<"Swag level over 9000 "<<endl;
}

system ("PAUSE");
return 0;
}

这是它给我的错误：[Error]Id 返回了 1 个退出状态，它突出显示了代码的 a='Nicu' 部分。尽管我在这段代码中使用了 char，但我仍然不知道它的作用，但至少我确定 int 不能与字母一起使用。

Answer 1

#include<iostream>
#include<cstdlib>
using namespace std;

int main()
{
string b, a;
a = "Nicu";
cout<<"Insert your name: ";
cin>>b;
if (b==a){
cout<<"Sorry ! Couldn't find swag in database... "<<endl;
}
else if (b!=a){
cout<<"Swag level over 9000 "<<endl;
}

system ("PAUSE");
return 0;
}

Answer 2

char用于存储单个字符。

您可以使用std::string来存储字符串。

重写，

#include <iostream>
#include <cstdlib>
#include <string>
using namespace std;

int main()
{
  string a = "Nicu";
  string b;
  cout<<"Insert your name: ";
  cin>>b;
  if (b==a){
    cout<<"Sorry ! Couldn't find swag in database... "<<endl;
  }
  else if (b!=a){
    cout<<"Swag level over 9000 "<<endl;
  }
  system ("PAUSE");
  return 0;
}

Answer 3

为什么不使用字符串而不是字符？？要比较字符串，您应该使用 "strcomp"

    #include <stdio.h>
    #include <string.h>
int main()
{
    string other;
    string that;
    if(strcmp(other, "hi")) // comparing the characters in this string with the text possibility "hi."
    {
    // do whatever you want if they are equal.
    }
    //Or.
    if(strcmp(other, that)) // comparing both strings rather than a string with a possibly extracted text to compare it with alongside another string comparing both strings at once.
    {
    // do whatever you want if they are equal.
    }
}

如何使变量等于 C++ 中的字母？

How to make a variable be equal to a letter in C++?

c++

char