如何 select 仅来自 table 的第二个最大日期

Question

我有一个 table 存储交货日期和订单号的地方。

在这里我可以得到最大交货日期的订单。

SELECT DISTINCT D.ORDER_NO
FROM DELIVERY D
WHERE D.CUSTOMER_NO =112 AND D.DELIVERY_DATE = (SELECT  MAX(D1.DELIVERY_DATE) FROM DELIVERY D1
WHERE D1.CUSTOMER_NO = 112 );

此处单个客户可能有多个订单。

现在我想要的是只获得第二个最大日期。

通过使用上述查询，我能够通过将 = 更改为 < 并在子查询中添加 ORDER BY 来获取最大交货日期以外的数据列表。

但是它是一个完整的列表，但我只想要第二个最大日期。

有人请告诉我如何才能只获得第二个最大日期。

注意：我试过使用 ROWNUM<=1 但我输入的日期不对

Answer 1

改变D.DELIVERY_DATE =

到D.DELIVERY_DATE <

SELECT DISTINCT D.ORDER_NO
    FROM DELIVERY D
    WHERE D.CUSTOMER_NO =112 AND D.DELIVERY_DATE = (SELECT  MAX(D1.DELIVERY_DATE) FROM DELIVERY D1
    WHERE D1.CUSTOMER_NO = 112 );

或类似下面的内容

SELECT MAX(DELIVERY_DATE)
  FROM TABLE
 WHERE DELIVERY_DATE< ( SELECT MAX(DELIVERY_DATE)
                 FROM TABLE)

Answer 2

SELECT * FROM(
SELECT DISTINCT D.ORDER_NO, ROW_NUMBER()OVER(order by D.DELIVERY_DATE desc) RowNo
FROM DELIVERY D
WHERE D.CUSTOMER_NO =112
) t where t.RowNo = 2

Answer 3

假设您使用的是 Oracle：

SELECT *
FROM
(
    SELECT t.*, rownum rnum
    FROM
    (
        SELECT DISTINCT D.ORDER_NO
        FROM DELIVERY D
        WHERE D.CUSTOMER_NO = 112
        ORDER BY D.DELIVERY_DATE DESC
    ) t
    WHERE rownum <= 2
)
WHERE rnum >= 2

Answer 4

  SELECT TOP 1 D.ORDER_NO
FROM DELIVERY D WHERE D.CUSTOMER_NO =112 
 AND D.DELIVERY_DATE = (SELECT  MAX(D1.DELIVERY_DATE) FROM DELIVERY D1 WHERE D1.CUSTOMER_NO = 112 );
 ORDER BY  DELIVERY_DATE  DESC

Answer 5

您可以试试这个查询：

SELECT DISTINCT ORDER_NO FROM DELIVERY WHERE CUSTOMER_NO=112 AND DELIVERY_DATE =
(SELECT MAX(DELIVERY_DATE) FROM DELIVERY WHERE CUSTOMER_NO=112 AND 
DELIVERY_DATE<(SELECT MAX(DELIVERY_DATE) FROM DELIVERY AND CUSTOMER_NO=112));

子查询将 return 第二个最大交货日期，这将给出 order_no 第二个最大交货日期。

Answer 6

SELECT D.ORDER_NO
FROM
(
SELECT DISTINCT D.ORDER_NO,D.DELIVERY_DATE,ROW_NUMBER()OVER(order by D.DELIVERY_DATE desc) RowNo
FROM DELIVERY D
WHERE D.CUSTOMER_NO =1128158 
ORDER BY D.DELIVERY_DATE DESC)
t WHERE t.RowNo = 2;

Answer 7

Select 第二个最大日期从 table

 SELECT MAX(date) FROM tbl_date WHERE date NOT IN (SELECT MAX(date) FROM tbl_date )
        OR
        SELECT DISTINCT date FROM tbl_date  ORDER BY date DESC LIMIT 1,1;
        OR
        SELECT MAX(date) FROM ( SELECT date FROM tbl_date  MINUS SELECT MAX(date) FROM tbl_date)

如何 select 仅来自 table 的第二个最大日期

How to select only the second max date from a table

sql

oracle

date

greatest-n-per-group