R：基于概率的 true/false 语句

Question

我有大量数据点，每个数据点都有不同的相关概率为 0 或 1。R 中是否有办法创建从这些概率中采样的 0 和 1 向量？下面的代码显示了如何做我想做的事，但它在循环中。

n <- 10
x <- letters[1:n] # my data
p <- runif(n) # my probabilities of the result being 1
result <- numeric()
for(ii in 1:n){
  result[ii] <- sample(x = c(0,1), 1, prob = c(1-p[ii], p[ii]))
}
print(cbind(x, p, result))

结果类似于：

      x   p                    result
[1,] "a" "0.0407166101504117" "0"   
[2,] "b" "0.632280522491783"  "1"   
[3,] "c" "0.754841333255172"  "0"   
[4,] "d" "0.0509465073700994" "0"   
[5,] "e" "0.629663853673264"  "0"   
[6,] "f" "0.357108945958316"  "0"   
[7,] "g" "0.808141406625509"  "1"   
[8,] "h" "0.671664241468534"  "1"   
[9,] "i" "0.0218871515244246" "1"   
[10,] "j" "0.689538966864347"  "1"

Answer 1

我不确定我是否理解正确，因为我被字母弄糊涂了......这个怎么样？

set.seed(1) # reproducibility
n <- 10
p <- runif(n) # probabilities
result <- rbinom(n,1,p)

cbind(p,result)
               p result
 [1,] 0.26550866      0
 [2,] 0.37212390      0
 [3,] 0.57285336      0
 [4,] 0.90820779      1
 [5,] 0.20168193      0
 [6,] 0.89838968      1
 [7,] 0.94467527      1
 [8,] 0.66079779      0
 [9,] 0.62911404      1
[10,] 0.06178627      0

R：基于概率的 true/false 语句

R: probability based true/false statements

r

probability