sql 查询中的 Sum 函数

Question

我有以下查询：

SELECT 
     cc.chain_desc as chain_desc 
    ,cc.chain_id as chain_id 
    ,COUNT(distinct t.trans_id) as TranCount
FROM TRANSACTION AS t 
LEFT OUTER JOIN location AS l 
ON t.location_id = l.location_id 
LEFT OUTER JOIN trans_line AS tl 
ON t.trans_id = tl.trans_id 
LEFT OUTER JOIN contract as c 
ON t.contract_id = c.contract_id 
LEFT OUTER JOIN chain_desc as cc 
ON l.chain_id = cc.chain_id 
WHERE 
t.loc_country = 'U' 
AND c.issuer_id IN (156966,166203) 
AND t.trans_date >= '2016-10-01 00:00' 
and t.trans_date < '2016-10-31 00:00'
AND tl.cat NOT IN ('DEF','DEFD','DEFC') 
GROUP BY cc.chain_desc, cc.chain_id 
ORDER BY cc.chain_desc, cc.chain_id

上面的查询执行后，得到以下结果：

我需要最后一列 "trancount" 的总和，即 490。我已尝试按如下方式更改查询：

SELECT 
     cc.chain_desc as chain_desc 
    ,cc.chain_id as chain_id 
    ,COUNT(distinct t.trans_id) as TranCount
    ,SUM(distinct t.trans_id)as TransSum
FROM TRANSACTION AS t 
LEFT OUTER JOIN location AS l 
ON t.location_id = l.location_id 
LEFT OUTER JOIN trans_line AS tl 
ON t.trans_id = tl.trans_id 
LEFT OUTER JOIN contract as c 
ON t.contract_id = c.contract_id 
LEFT OUTER JOIN chain_desc as cc 
ON l.chain_id = cc.chain_id 
WHERE 
t.loc_country = 'U'
AND c.issuer_id IN (156966,166203) 
AND t.trans_date >= '2016-10-01 00:00' 
and t.trans_date < '2016-10-31 00:00'
AND tl.cat NOT IN ('DEF','DEFD','DEFC')
GROUP BY cc.chain_desc, cc.chain_id 
ORDER BY cc.chain_desc, cc.chain_id

但是我没有得到预期的结果。对 transcount 列进行求和的正确方法是什么？

Answer 1

SELECT 
     cc.chain_desc as chain_desc 
    ,cc.chain_id as chain_id 
    ,COUNT(distinct t.trans_id) as TranCount
FROM TRANSACTION AS t 
LEFT OUTER JOIN location AS l 
ON t.location_id = l.location_id 
LEFT OUTER JOIN trans_line AS tl 
ON t.trans_id = tl.trans_id 
LEFT OUTER JOIN contract as c 
ON t.contract_id = c.contract_id 
LEFT OUTER JOIN chain_desc as cc 
ON l.chain_id = cc.chain_id 
WHERE 
t.loc_country = 'U' 
AND c.issuer_id IN (156966,166203) 
AND t.trans_date >= '2016-10-01 00:00' 
and t.trans_date < '2016-10-31 00:00'
AND tl.cat NOT IN ('DEF','DEFD','DEFC') 
GROUP BY GROUPING SETS ((cc.chain_desc, cc.chain_id), ())
ORDER BY cc.chain_desc, cc.chain_id

Group by grouping sets 允许您进行多级聚合那些未聚合的值将 Reuther NULL

或者如果 MySQL...

你可能需要汇总

SELECT 
     cc.chain_desc as chain_desc 
    ,cc.chain_id as chain_id 
    ,COUNT(distinct t.trans_id) as TranCount
FROM TRANSACTION AS t 
LEFT OUTER JOIN location AS l 
ON t.location_id = l.location_id 
LEFT OUTER JOIN trans_line AS tl 
ON t.trans_id = tl.trans_id 
LEFT OUTER JOIN contract as c 
ON t.contract_id = c.contract_id 
LEFT OUTER JOIN chain_desc as cc 
ON l.chain_id = cc.chain_id 
WHERE 
t.loc_country = 'U' 
AND c.issuer_id IN (156966,166203) 
AND t.trans_date >= '2016-10-01 00:00' 
and t.trans_date < '2016-10-31 00:00'
AND tl.cat NOT IN ('DEF','DEFD','DEFC') 
GROUP BY cc.chain_desc, cc.chain_id with Rollup 
ORDER BY cc.chain_desc, cc.chain_id

Answer 2

== 编辑版本 == 尝试（在 SQL 服务器中）：

SELECT 
     chain_desc
    ,chain_id
    ,TranCount
    ,SUM(TranCount) OVER (PARTITION BY 1) as TransSum
    (
        SELECT 
             cc.chain_desc as chain_desc 
            ,cc.chain_id as chain_id 
            ,COUNT(distinct t.trans_id) as TranCount
        FROM TRANSACTION AS t 
        LEFT OUTER JOIN location AS l 
        ON t.location_id = l.location_id 
        LEFT OUTER JOIN trans_line AS tl 
        ON t.trans_id = tl.trans_id 
        LEFT OUTER JOIN contract as c 
        ON t.contract_id = c.contract_id 
        LEFT OUTER JOIN chain_desc as cc 
        ON l.chain_id = cc.chain_id 
        WHERE 
        t.loc_country = 'U' 
        AND c.issuer_id IN (156966,166203) 
        AND t.trans_date >= '2016-10-01 00:00' 
        and t.trans_date < '2016-10-31 00:00'
        AND tl.cat NOT IN ('DEF','DEFD','DEFC') 
        GROUP BY cc.chain_desc, cc.chain_id 
    ) as a
    ORDER BY chain_desc, chain_id

并删除 GROUP BY

sql 查询中的 Sum 函数

Sum function in a sql query

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