lambda 表达式树的空检查

Question

如何检查 String 类型的属性是否为 null，以便我的以下代码能够正常工作并且在方法调用期间不会失败？

if (SelectedOperator is StringOperators)
{
    MethodInfo method;

    var value = Expression.Constant(Value);

    switch ((StringOperators)SelectedOperator)
    {
        case StringOperators.Is:
            condition = Expression.Equal(property, value);
            break;

        case StringOperators.IsNot:
            condition = Expression.NotEqual(property, value);
            break;

        case StringOperators.StartsWith:
            method = typeof(string).GetMethod("StartsWith", new[] { typeof(string) });
            condition = Expression.Call(property, method, value);
            break;

        case StringOperators.Contains:
            method = typeof(string).GetMethod("Contains", new[] { typeof(string) });
            condition = Expression.Call(property, method, value);
            break;

        case StringOperators.EndsWith:
            method = typeof(string).GetMethod("EndsWith", new[] { typeof(string) });
            condition = Expression.Call(property, method, value);
            break;
    }
}

Answer 1

使用 AndAlso 向结果表达式添加空检查，如下所示：

// Your switch stays as is
switch ((StringOperators)SelectedOperator) {
    case StringOperators.Is:
        condition = Expression.Equal(property, value);
        break;
    ...
}
// Create null checker property != null
var nullCheck = Expression.NotEqual(property, Expression.Constant(null, typeof(object)));
// Add null checker in front of the condition using &&
condition = Expression.AndAlso(nullCheck, condition);

lambda 表达式树的空检查

Null check for lambda expression tree

c#

lambda