EXC_BAD_INSTRUCTION 尝试在 Swift Playground 中打印函数时出错
EXC_BAD_INSTRUCTION error when attempting to print a function in Swift Playground
我目前正在做一个大学数学项目,该项目要求我创建一个与抵押贷款相关的应用程序。我正在尝试编写 Swift 代码来计算抵押贷款的每个月支付的本金和利息。
我写的代码如下(值得一提的是我对编码还很陌生,对Python有一点经验,这都是自学的,所以欢迎任何批评!):
// Declare all variables
// y = periodic interest rate
// n = time left of repayment period (months)
let y = [Float](arrayLiteral: 0.02/12,0.03/12,0.04/12,0.05/12)
let n = [Float](arrayLiteral: 240,180,120,60)
var x = [Float]()
var interest = [Float]()
var T_1 = [Int]()
// Create Array from 0 to 240
for a in 0...240 {
T_1.append(a)
}
// Create Array of all 240 interest values
for a in 0...239 {
if a < 60 {
interest.append(y[0])
var repay = n[0]
x.append(repay)
}
else if a < 120 {
interest.append(y[1])
var repay = n[1]
x.append(repay)
}
else if a < 180 {
interest.append(y[2])
var repay = n[2]
x.append(repay)
}
else {
interest.append(y[3])
var repay = n[3]
x.append(repay)
}
}
print("Interest array:",interest)
// Calculate Each months Principal paid and Interest Paid
func variablerate(P: inout Float) -> [Float] {
var principal = [Float]()
var i_paid = [Float]()
var repayments = [Float]()
var R = Float(0)
let temporaryP = P
i_paid.append(0)
for a in 0...240 {
if (a>0) && (a<240) && (interest[a-1] == interest[a]) {
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
P = (1+interest[a-1])*temporaryP
P = P-R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
}
else if a==240 || a==241 {
P = P - R
principal.append(round(100*P)/100)
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
let h = interest[a-1]
P = P*(1+h)
}
else {
P = P - R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
let ip = P*(1+interest[a])-P
i_paid.append(i_paid[a-1] + ip)
P = P*(1+h)
}
}
return i_paid
return principal
}
var z = Float(100000)
print(variablerate(P: &z)) //This is where the error appears
给出的错误是:
error: Execution was interrupted, reason: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP,subcode=0x0).
非常感谢有关此问题的任何帮助或指导!
崩溃原因是索引超出范围。
您正在获取索引超出范围异常,因为在代码中您是 运行 从 0 到 240 的循环,并且从局部变量 a 减去 1 所以首先迭代 a 将包含 0,从 0 中减去 1 将得到负索引。
这里是错误的
对于 0...240 {
如果 (a>0) && (a<240) && (兴趣[a-1] == 兴趣[a])
以下代码已更正
// Declare all variables
// y = periodic interest rate
// n = time left of repayment period (months)
let y = [Float](arrayLiteral: 0.02/12,0.03/12,0.04/12,0.05/12)
let n = [Float](arrayLiteral: 240,180,120,60)
var x = [Float]()
var interest = [Float]()
var T_1 = [Int]()
// Create Array from 0 to 240
for a in 0...240 {
T_1.append(a)
}
// Create Array of all 240 interest values
for a in 0...239 {
if a < 60 {
interest.append(y[0])
var repay = n[0]
x.append(repay)
}
else if a < 120 {
interest.append(y[1])
var repay = n[1]
x.append(repay)
}
else if a < 180 {
interest.append(y[2])
var repay = n[2]
x.append(repay)
}
else {
interest.append(y[3])
var repay = n[3]
x.append(repay)
}
}
print("Interest array:",interest)
// Calculate Each months Principal paid and Interest Paid
func variablerate(P: inout Float) -> [Float] {
var principal = [Float]()
var i_paid = [Float]()
var repayments = [Float]()
var R = Float(0)
let temporaryP = P
i_paid.append(0)
for a in 1...240 { // Code corrected now loop go from 1 to 240
if (a>0) && (a<240) && (interest[a-1] == interest[a]) {
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
P = (1+interest[a-1])*temporaryP
P = P-R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
}
else if a == 240 || a == 241 {
P = P - R
principal.append(round(100*P)/100)
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
let h = interest[a-1]
P = P*(1+h)
}
else {
P = P - R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
let ip = P*(1+interest[a])-P
i_paid.append(i_paid[a-1] + ip)
P = P*(1+h)
}
}
//return i_paid
return principal
}
var z = Float(100000)
print("\(variablerate(P: &z))")
我目前正在做一个大学数学项目,该项目要求我创建一个与抵押贷款相关的应用程序。我正在尝试编写 Swift 代码来计算抵押贷款的每个月支付的本金和利息。
我写的代码如下(值得一提的是我对编码还很陌生,对Python有一点经验,这都是自学的,所以欢迎任何批评!):
// Declare all variables
// y = periodic interest rate
// n = time left of repayment period (months)
let y = [Float](arrayLiteral: 0.02/12,0.03/12,0.04/12,0.05/12)
let n = [Float](arrayLiteral: 240,180,120,60)
var x = [Float]()
var interest = [Float]()
var T_1 = [Int]()
// Create Array from 0 to 240
for a in 0...240 {
T_1.append(a)
}
// Create Array of all 240 interest values
for a in 0...239 {
if a < 60 {
interest.append(y[0])
var repay = n[0]
x.append(repay)
}
else if a < 120 {
interest.append(y[1])
var repay = n[1]
x.append(repay)
}
else if a < 180 {
interest.append(y[2])
var repay = n[2]
x.append(repay)
}
else {
interest.append(y[3])
var repay = n[3]
x.append(repay)
}
}
print("Interest array:",interest)
// Calculate Each months Principal paid and Interest Paid
func variablerate(P: inout Float) -> [Float] {
var principal = [Float]()
var i_paid = [Float]()
var repayments = [Float]()
var R = Float(0)
let temporaryP = P
i_paid.append(0)
for a in 0...240 {
if (a>0) && (a<240) && (interest[a-1] == interest[a]) {
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
P = (1+interest[a-1])*temporaryP
P = P-R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
}
else if a==240 || a==241 {
P = P - R
principal.append(round(100*P)/100)
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
let h = interest[a-1]
P = P*(1+h)
}
else {
P = P - R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
let ip = P*(1+interest[a])-P
i_paid.append(i_paid[a-1] + ip)
P = P*(1+h)
}
}
return i_paid
return principal
}
var z = Float(100000)
print(variablerate(P: &z)) //This is where the error appears
给出的错误是:
error: Execution was interrupted, reason: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP,subcode=0x0).
非常感谢有关此问题的任何帮助或指导!
崩溃原因是索引超出范围。
您正在获取索引超出范围异常,因为在代码中您是 运行 从 0 到 240 的循环,并且从局部变量 a 减去 1 所以首先迭代 a 将包含 0,从 0 中减去 1 将得到负索引。
这里是错误的
对于 0...240 {
如果 (a>0) && (a<240) && (兴趣[a-1] == 兴趣[a])
以下代码已更正
// Declare all variables
// y = periodic interest rate
// n = time left of repayment period (months)
let y = [Float](arrayLiteral: 0.02/12,0.03/12,0.04/12,0.05/12)
let n = [Float](arrayLiteral: 240,180,120,60)
var x = [Float]()
var interest = [Float]()
var T_1 = [Int]()
// Create Array from 0 to 240
for a in 0...240 {
T_1.append(a)
}
// Create Array of all 240 interest values
for a in 0...239 {
if a < 60 {
interest.append(y[0])
var repay = n[0]
x.append(repay)
}
else if a < 120 {
interest.append(y[1])
var repay = n[1]
x.append(repay)
}
else if a < 180 {
interest.append(y[2])
var repay = n[2]
x.append(repay)
}
else {
interest.append(y[3])
var repay = n[3]
x.append(repay)
}
}
print("Interest array:",interest)
// Calculate Each months Principal paid and Interest Paid
func variablerate(P: inout Float) -> [Float] {
var principal = [Float]()
var i_paid = [Float]()
var repayments = [Float]()
var R = Float(0)
let temporaryP = P
i_paid.append(0)
for a in 1...240 { // Code corrected now loop go from 1 to 240
if (a>0) && (a<240) && (interest[a-1] == interest[a]) {
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
P = (1+interest[a-1])*temporaryP
P = P-R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
}
else if a == 240 || a == 241 {
P = P - R
principal.append(round(100*P)/100)
let ip = P*(1+interest[a-1])-P
i_paid.append(i_paid[a-1] + ip)
let h = interest[a-1]
P = P*(1+h)
}
else {
P = P - R
let h = interest[a]
R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
repayments.append(R)
principal.append(round(100*P)/100)
let ip = P*(1+interest[a])-P
i_paid.append(i_paid[a-1] + ip)
P = P*(1+h)
}
}
//return i_paid
return principal
}
var z = Float(100000)
print("\(variablerate(P: &z))")