Excel：以逗号分隔的单个单元格数字

Question

我在单个 Excel 单元格中有一串数字，用逗号分隔，例如A2 = "4,3,2,7"。我想要一个公式能够将单元格 B2 中的这些数字除以 2，例如B2 = "2,1,1,3"（奇数应向下取整而不是向上取整）

公式需要能够占：
- 更小或更大的数字串
- 对于单位数和双位数
- 偶数或奇数
- 没有 VBA
- 公式可以使用多列但不能使用分隔文本到列功能（由于单元格位置）

我能够得到一个公式来对 A2 (4,3,2,7 = 16) 中的数字字符串求和，但不能除以 2。我对字符串求和的公式如下。感谢任何帮助，谢谢！

{=SUM(IF(ISERR(VALUE(MID(A2,ROW($A:OFFSET($A,LEN(A2)-1,0‌)),1))),0,VALUE(MID(‌A2,ROW($A:OFFSET($‌A,LEN(A2)-1,0)),1)‌)))}

Answer 1

在您的示例中，将此公式用于单元格 B1:

=SUBSTITUTE(SUBSTITUTE(A1,",","000")/2,"000",",")

那么结果是这样的：

 |    A    |    B    |
 +---------+---------+  
1| 4,2,6,8 | 2,1,3,4 |
2|

Answer 2

嗯，这是我第二次尝试解决（我希望）您的问题。如果您的字符串在单元格 A2 中，则将此代码放入单元格 B2:

=LEFT(IFERROR(ROUNDDOWN(MID(A2,1,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,3,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,5,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,7,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,9,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,11,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,13,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,15,1)/2,0),""),LEN(A2))

它最多可以处理 8 个数字字符串，以及奇数。

更新

这个公式可以处理两位数，但它只支持 1 到 4 个字符串数字（例如 (25,5,36,48)）：

=LEFT(IFERROR(ROUNDDOWN(MID(A2,1,IFERROR(SEARCH(",",A2,1)-1,LEN(A2)))/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,SEARCH(",",A2,1)+1,IFERROR(SEARCH(",",A2,SEARCH(",",A2,1)+1)-SEARCH(",",A2,1)-1,LEN(A2)-SEARCH(",",A2,1)))/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1,IFERROR(SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)-SEARCH(",",A2,SEARCH(",",A2,1)+1)-1,LEN(A2)-SEARCH(",",A2,SEARCH(",",A2,1))))/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)+1,IFERROR(SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)+1)-SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)-1,LEN(A2)-SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)))/2,0),""),LEN(A2))

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