无法解析 docker 个相关的 sbt 标签

Can't resolve docker related sbt tags

我正在尝试将 sbt-docker 添加到我的游戏网站的 sbt 构建中,但我 运行 遇到了问题。由于某些原因,底部的docker相关内容的none可以解决。

project/plugins.sbt

logLevel := Level.Warn

resolvers ++= Seq(
    "Typesafe repository" at "http://repo.typesafe.com/typesafe/releases/"
)

addSbtPlugin("com.typesafe.play" % "sbt-plugin" % "2.5.9")

build.sbt

name := "personal_site"

version := "1.1"

lazy val `personal_site` = (project in file(".")).enablePlugins(PlayScala,DockerPlugin)

scalaVersion := "2.11.7"

libraryDependencies ++= Seq( jdbc , cache , ws , specs2 % Test )

unmanagedResourceDirectories in Test <+=  baseDirectory ( _ /"target/web/public/test" )  

resolvers += "scalaz-bintray" at "https://dl.bintray.com/scalaz/releases"

dockerfile in docker := {
    val targetDir = "/usr/src"

    new Dockerfile {
        from("flurdy/activator")
        //More goes here
    }
}

imageNames in docker := Seq(
    // Sets the latest tag
    ImageName(s"${name.value}:latest"),

    // Sets a name with a tag that contains the project version
    ImageName(
        namespace = None,
        repository = name.value,
        tag = Some("v" + version.value)
    )
)

这是它在 IntelliJ 中的样子

我也试过将 addSbtPlugin("se.marcuslonnberg" % "sbt-docker" % "1.4.0") 添加到我的 project/plugins.sbt 但我收到关于 DockerPlugin 被导入两次的错误。

~/Sync/Projects/Programming/Personal_Site (master ✘)✹ ᐅ  sbt clean
[info] Loading project definition from /home/ryan/Sync/Projects/Programming/Personal_Site/project
/home/ryan/Sync/Projects/Programming/Personal_Site/build.sbt:5: error: reference to DockerPlugin is ambiguous;
it is imported twice in the same scope by
import _root_.sbtdocker.DockerPlugin
and import _root_.com.typesafe.sbt.packager.docker.DockerPlugin
lazy val `personal_site` = (project in file(".")).enablePlugins(PlayScala,DockerPlugin)

尝试将您的 build.sbt 配置更改为此。

lazy val root = (project in file(".")).enablePlugins(sbtdocker.DockerPlugin, PlayScala)

它通过使用 Docker 插件的全名来消除歧义,因为我相信 sbt-native-packager 对其 Docker 插件使用相同的名称。

也许值得向作者的回购提出 Github 问题,以便他们可以在项目文档中记录它。